Guava BigIntegerMath類的floorPowerOfTwo(BigInteger x)方法返回小於或等於x的2的最大冪。這等效於BigInteger.valueOf(2).pow(log2(x,FLOOR))。
用法:
public static BigInteger floorPowerOfTwo(BigInteger x)
參數:此方法將BigInteger x作為其底方冪為2的參數。
返回值:此方法返回小於或等於x的2的最大冪。
異常:如果x <= 0,則此方法引發IllegalArgumentException。
以下示例說明了BifIntegerMath.floorPowerOfTwo()方法:
範例1:
// Java code to show implementation of
// floorPowerOfTwo() method
// of Guava's BigIntegerMath class
import java.math.*;
import com.google.common.math.BigIntegerMath;
class GFG {
// Driver code
public static void main(String args[])
{
BigInteger n1 = BigInteger.valueOf(10);
// Using floorPowerOfTwo(BigInteger x) method
// of Guava's BigIntegerMath class
BigInteger
ans1
= BigIntegerMath.floorPowerOfTwo(n1);
System.out.println("Largest power of 2 less "
+ "than or equal to " + n1
+ " is:" + ans1);
BigInteger n2 = BigInteger.valueOf(127);
// Using floorPowerOfTwo(BigInteger x) method
// of Guava's BigIntegerMath class
BigInteger
ans2
= BigIntegerMath.floorPowerOfTwo(n2);
System.out.println("Largest power of 2 less "
+ "than or equal to " + n2
+ " is:" + ans2);
}
}
輸出:
Largest power of 2 less than or equal to 10 is:8 Largest power of 2 less than or equal to 127 is:64
範例2:顯示IllegalArgumentException
// Java code to show implementation of
// floorPowerOfTwo(BigInteger x) method
// of Guava's BigIntegerMath class
import java.math.*;
import com.google.common.math.BigIntegerMath;
class GFG {
// Driver code
public static void main(String args[])
{
try {
BigInteger n1 = BigInteger.valueOf(-3);
// Using floorPowerOfTwo(BigInteger x) method
// of Guava's BigIntegerMath class
// This should raise "IllegalArgumentException"
// as x <= 0
BigInteger
ans1
= BigIntegerMath.floorPowerOfTwo(n1);
System.out.println("Largest power of 2 less "
+ "than or equal to " + n1
+ " is:" + ans1);
}
catch (Exception e) {
System.out.println("Exception:" + e);
}
}
}
輸出:
Exception:java.lang.IllegalArgumentException:x (-3) must be > 0
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注:本文由純淨天空篩選整理自Sahil_Bansall大神的英文原創作品 BigIntegerMath floorPowerOfTwo() function | Guava | Java。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。