本文整理匯總了VB.NET中System.Net.WebClient.UploadFile方法的典型用法代碼示例。如果您正苦於以下問題：VB.NET WebClient.UploadFile方法的具體用法？VB.NET WebClient.UploadFile怎麽用？VB.NET WebClient.UploadFile使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類System.Net.WebClient的用法示例。
在下文中一共展示了WebClient.UploadFile方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的VB.NET代碼示例。
示例1: WebClient
Console.Write(ControlChars.Cr + "Please enter the URI to post data to : ")
Dim uriString As String = Console.ReadLine()
' Create a new WebClient instance.
Dim myWebClient As New WebClient()
Console.WriteLine(ControlChars.Cr & _
"Please enter the fully qualified path of the file to be uploaded to the URI")
Dim fileName As String = Console.ReadLine()
Console.WriteLine("Uploading {0} to {1} ...", fileName, uriString)
' Upload the file to the URI.
' The 'UploadFile(uriString,fileName)' method implicitly uses HTTP POST method.
Dim responseArray As Byte() = myWebClient.UploadFile(uriString, fileName)
' Decode and display the response.
Console.WriteLine(ControlChars.Cr & "Response Received.The contents of the file uploaded are: " & _
ControlChars.Cr & "{0}", System.Text.Encoding.ASCII.GetString(responseArray))示例2: WebClient
Console.Write(ControlChars.Cr + "Please enter the URL to post data to : ")
Dim uriString As String = Console.ReadLine()
' Create a new WebClient instance.
Dim myWebClient As New WebClient()
Console.WriteLine(ControlChars.Cr & _
"Please enter the fully qualified path of the file to be uploaded to the URL")
Dim fileName As String = Console.ReadLine()
Console.WriteLine("Uploading {0} to {1} ...", fileName, uriString)
' Upload the file to the Url using the HTTP 1.0 POST.
Dim responseArray As Byte() = myWebClient.UploadFile(uriString, "POST", fileName)
' Decode and display the response.
Console.WriteLine(ControlChars.Cr + "Response Received.The contents of the file uploaded are: " & _
ControlChars.Cr & "{0}", System.Text.Encoding.ASCII.GetString(responseArray))