本文整理匯總了VB.NET中System.Linq.Enumerable.GroupBy方法的典型用法代碼示例。如果您正苦於以下問題:VB.NET Enumerable.GroupBy方法的具體用法?VB.NET Enumerable.GroupBy怎麽用?VB.NET Enumerable.GroupBy使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。
在下文中一共展示了Enumerable.GroupBy方法的4個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的VB.NET代碼示例。
示例1: List
Structure Pet
Public Name As String
Public Age As Double
End Structure
Public Sub GroupByEx4()
' Create a list of pets.
Dim petsList As New List(Of Pet)(New Pet() _
{New Pet With {.Name = "Barley", .Age = 8.3},
New Pet With {.Name = "Boots", .Age = 4.9},
New Pet With {.Name = "Whiskers", .Age = 1.5},
New Pet With {.Name = "Daisy", .Age = 4.3}})
' Group Pet.Age values by the Math.Floor of the age.
' Then project an anonymous type from each group
' that consists of the key, the count of the group's
' elements, and the minimum and maximum age in the group.
Dim query = petsList.GroupBy(
Function(pet) Math.Floor(pet.Age),
Function(pet) pet.Age,
Function(baseAge, ages) New With
{.Key = baseAge,
.Count = ages.Count(),
.Min = ages.Min(),
.Max = ages.Max()}
)
Dim output As New System.Text.StringBuilder
' Iterate over each anonymous type.
For Each result In query
output.AppendLine(vbCrLf & "Age group: " & result.Key)
output.AppendLine("Number of pets in this age group: " & result.Count)
output.AppendLine("Minimum age: " & result.Min)
output.AppendLine("Maximum age: " & result.Max)
Next
' Display the output.
Console.WriteLine(output.ToString)
End Sub
輸出:
Age group: 8 Number of pets in this age group: 1 Minimum age: 8.3 Maximum age: 8.3 Age group: 4 Number of pets in this age group: 2 Minimum age: 4.3 Maximum age: 4.9 Age group: 1 Number of pets in this age group: 1 Minimum age: 1.5 Maximum age: 1.5
示例2: GroupByEx1
Structure Pet
Public Name As String
Public Age As Integer
End Structure
Sub GroupByEx1()
'Create a list of Pet objects.
Dim pets As New List(Of Pet)(New Pet() _
{New Pet With {.Name = "Barley", .Age = 8},
New Pet With {.Name = "Boots", .Age = 4},
New Pet With {.Name = "Whiskers", .Age = 1},
New Pet With {.Name = "Daisy", .Age = 4}})
' Group the pets using Age as the key
' and selecting only the pet's Name for each value.
Dim query As IEnumerable(Of IGrouping(Of Integer, String)) =
pets.GroupBy(Function(pet) pet.Age,
Function(pet) pet.Name)
Dim output As New System.Text.StringBuilder
' Iterate over each IGrouping in the collection.
For Each petGroup As IGrouping(Of Integer, String) In query
' Print the key value of the IGrouping.
output.AppendLine(petGroup.Key)
' Iterate over each value in the IGrouping and print the value.
For Each name As String In petGroup
output.AppendLine(" " & name)
Next
Next
' Display the output.
Console.WriteLine(output.ToString)
End Sub
輸出:
8 Barley 4 Boots Daisy 1 Whiskers
示例3:
Dim query =
From pet In pets
Group pet.Name By Age = pet.Age Into ageGroup = Group
示例4: List
Structure Pet
Public Name As String
Public Age As Double
End Structure
Public Sub GroupByEx3()
' Create a list of pets.
Dim petsList As New List(Of Pet)(New Pet() _
{New Pet With {.Name = "Barley", .Age = 8.3},
New Pet With {.Name = "Boots", .Age = 4.9},
New Pet With {.Name = "Whiskers", .Age = 1.5},
New Pet With {.Name = "Daisy", .Age = 4.3}})
' Group Pet objects by the Math.Floor of their age.
' Then project an anonymous type from each group
' that consists of the key, the count of the group's
' elements, and the minimum and maximum age in the group.
Dim query = petsList.GroupBy(
Function(pet) Math.Floor(pet.Age),
Function(age, pets) New With
{.Key = age,
.Count = pets.Count(),
.Min = pets.Min(Function(pet) pet.Age),
.Max = pets.Max(Function(Pet) Pet.Age)}
)
Dim output As New System.Text.StringBuilder
' Iterate over each anonymous type.
For Each result In query
output.AppendLine(vbCrLf & "Age group: " & result.Key)
output.AppendLine("Number of pets in this age group: " & result.Count)
output.AppendLine("Minimum age: " & result.Min)
output.AppendLine("Maximum age: " & result.Max)
Next
' Display the output.
Console.WriteLine(output.ToString)
End Sub
輸出:
Age group: 8 Number of pets in this age group: 1 Minimum age: 8.3 Maximum age: 8.3 Age group: 4 Number of pets in this age group: 2 Minimum age: 4.3 Maximum age: 4.9 Age group: 1 Number of pets in this age group: 1 Minimum age: 1.5 Maximum age: 1.5