本文整理匯總了VB.NET中System.Data.DataTable.ReadXmlSchema方法的典型用法代碼示例。如果您正苦於以下問題：VB.NET DataTable.ReadXmlSchema方法的具體用法？VB.NET DataTable.ReadXmlSchema怎麽用？VB.NET DataTable.ReadXmlSchema使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類System.Data.DataTable的用法示例。
在下文中一共展示了DataTable.ReadXmlSchema方法的4個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的VB.NET代碼示例。
示例1: DemonstrateReadWriteXMLSchemaWithReader
Private Sub DemonstrateReadWriteXMLSchemaWithReader()
Dim table As DataTable = CreateTestTable("XmlDemo")
PrintSchema(table, "Original table")
' Write the schema to XML in a memory stream.
Dim xmlStream As New System.IO.MemoryStream()
table.WriteXmlSchema(xmlStream)
' Rewind the memory stream.
xmlStream.Position = 0
Dim newTable As New DataTable
Dim reader As New System.Xml.XmlTextReader(xmlStream)
newTable.ReadXmlSchema(reader)
' Print out values in the table.
PrintSchema(newTable, "New Table")
End Sub
Private Function CreateTestTable(ByVal tableName As String) _
As DataTable
' Create a test DataTable with two columns and a few rows.
Dim table As New DataTable(tableName)
Dim column As New DataColumn("id", GetType(System.Int32))
column.AutoIncrement = True
table.Columns.Add(column)
column = New DataColumn("item", GetType(System.String))
table.Columns.Add(column)
' Add ten rows.
Dim row As DataRow
For i As Integer = 0 To 9
row = table.NewRow()
row("item") = "item " & i
table.Rows.Add(row)
Next i
table.AcceptChanges()
Return table
End Function
Private Sub PrintSchema(ByVal table As DataTable, _
ByVal label As String)
' Display the schema of the supplied DataTable:
Console.WriteLine(label)
For Each column As DataColumn In table.Columns
Console.WriteLine("{0}{1}: {2}", ControlChars.Tab, _
column.ColumnName, column.DataType.Name)
Next column
End Sub示例2: DemonstrateReadWriteXMLSchemaWithFile
Private Sub DemonstrateReadWriteXMLSchemaWithFile()
Dim table As DataTable = CreateTestTable("XmlDemo")
PrintSchema(table, "Original table")
Dim xmlFile As String = "SchemaDemo.xml"
' Write the schema to XML.
table.WriteXmlSchema(xmlFile)
Dim newTable As New DataTable
newTable.ReadXmlSchema(xmlFile)
' Print out values in the table.
PrintSchema(newTable, "New Table")
End Sub
Private Function CreateTestTable(ByVal tableName As String) _
As DataTable
' Create a test DataTable with two columns and a few rows.
Dim table As New DataTable(tableName)
Dim column As New DataColumn("id", GetType(System.Int32))
column.AutoIncrement = True
table.Columns.Add(column)
column = New DataColumn("item", GetType(System.String))
table.Columns.Add(column)
' Add ten rows.
Dim row As DataRow
For i As Integer = 0 To 9
row = table.NewRow()
row("item") = "item " & i
table.Rows.Add(row)
Next i
table.AcceptChanges()
Return table
End Function
Private Sub PrintSchema(ByVal table As DataTable, _
ByVal label As String)
' Display the schema of the supplied DataTable:
Console.WriteLine(label)
For Each column As DataColumn In table.Columns
Console.WriteLine("{0}{1}: {2}", ControlChars.Tab, _
column.ColumnName, column.DataType.Name)
Next column
End Sub示例3: DemonstrateReadWriteXMLSchemaWithReader
Private Sub DemonstrateReadWriteXMLSchemaWithReader()
Dim table As DataTable = CreateTestTable("XmlDemo")
PrintSchema(table, "Original table")
' Write the schema to XML in a memory stream.
Dim xmlStream As New System.IO.MemoryStream()
table.WriteXmlSchema(xmlStream)
' Rewind the memory stream.
xmlStream.Position = 0
Dim newTable As New DataTable
Dim reader As New System.IO.StreamReader(xmlStream)
newTable.ReadXmlSchema(reader)
' Print out values in the table.
PrintSchema(newTable, "New Table")
End Sub
Private Function CreateTestTable(ByVal tableName As String) _
As DataTable
' Create a test DataTable with two columns and a few rows.
Dim table As New DataTable(tableName)
Dim column As New DataColumn("id", GetType(System.Int32))
column.AutoIncrement = True
table.Columns.Add(column)
column = New DataColumn("item", GetType(System.String))
table.Columns.Add(column)
' Add ten rows.
Dim row As DataRow
For i As Integer = 0 To 9
row = table.NewRow()
row("item") = "item " & i
table.Rows.Add(row)
Next i
table.AcceptChanges()
Return table
End Function
Private Sub PrintSchema(ByVal table As DataTable, _
ByVal label As String)
' Display the schema of the supplied DataTable:
Console.WriteLine(label)
For Each column As DataColumn In table.Columns
Console.WriteLine("{0}{1}: {2}", ControlChars.Tab, _
column.ColumnName, column.DataType.Name)
Next column
End Sub示例4: DemonstrateReadWriteXMLSchemaWithStream
Private Sub DemonstrateReadWriteXMLSchemaWithStream()
Dim table As DataTable = CreateTestTable("XmlDemo")
PrintSchema(table, "Original table")
' Write the schema to XML in a memory stream.
Dim xmlStream As New System.IO.MemoryStream()
table.WriteXmlSchema(xmlStream)
' Rewind the memory stream.
xmlStream.Position = 0
Dim newTable As New DataTable
newTable.ReadXmlSchema(xmlStream)
' Print out values in the table.
PrintSchema(newTable, "New Table")
End Sub
Private Function CreateTestTable(ByVal tableName As String) _
As DataTable
' Create a test DataTable with two columns and a few rows.
Dim table As New DataTable(tableName)
Dim column As New DataColumn("id", GetType(System.Int32))
column.AutoIncrement = True
table.Columns.Add(column)
column = New DataColumn("item", GetType(System.String))
table.Columns.Add(column)
' Add ten rows.
Dim row As DataRow
For i As Integer = 0 To 9
row = table.NewRow()
row("item") = "item " & i
table.Rows.Add(row)
Next i
table.AcceptChanges()
Return table
End Function
Private Sub PrintSchema(ByVal table As DataTable, _
ByVal label As String)
' Display the schema of the supplied DataTable:
Console.WriteLine(label)
For Each column As DataColumn In table.Columns
Console.WriteLine("{0}{1}: {2}", ControlChars.Tab, _
column.ColumnName, column.DataType.Name)
Next column
End Sub