本文整理匯總了TypeScript中vs/platform/keybinding/common/keybindingResolver.KeybindingResolver.resolve方法的典型用法代碼示例。如果您正苦於以下問題：TypeScript KeybindingResolver.resolve方法的具體用法？TypeScript KeybindingResolver.resolve怎麽用？TypeScript KeybindingResolver.resolve使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類vs/platform/keybinding/common/keybindingResolver.KeybindingResolver的用法示例。
在下文中一共展示了KeybindingResolver.resolve方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的TypeScript代碼示例。
示例1: test
test('resolve key', function () {
let keybinding = KeyMod.CtrlCmd | KeyMod.Shift | KeyCode.KEY_Z;
let runtimeKeybinding = createSimpleKeybinding(keybinding, OS);
let contextRules = ContextKeyExpr.equals('bar', 'baz');
let keybindingItem = kbItem(keybinding, 'yes', null, contextRules, true);
assert.equal(KeybindingResolver.contextMatchesRules(createContext({ bar: 'baz' }), contextRules), true);
assert.equal(KeybindingResolver.contextMatchesRules(createContext({ bar: 'bz' }), contextRules), false);
let resolver = new KeybindingResolver([keybindingItem], []);
assert.equal(resolver.resolve(createContext({ bar: 'baz' }), null, getDispatchStr(runtimeKeybinding))!.commandId, 'yes');
assert.equal(resolver.resolve(createContext({ bar: 'bz' }), null, getDispatchStr(runtimeKeybinding)), null);
});示例2: createKeybinding
let testResolve = (ctx: IContext, _expectedKey: number, commandId: string) => {
const expectedKey = createKeybinding(_expectedKey, OS)!;
let previousPart: (string | null) = null;
for (let i = 0, len = expectedKey.parts.length; i < len; i++) {
let part = getDispatchStr(expectedKey.parts[i]);
let result = resolver.resolve(ctx, previousPart, part);
if (i === len - 1) {
// if it's the final part, then we should find a valid command,
// and there should not be a chord.
assert.ok(result !== null, `Enters chord for ${commandId} at part ${i}`);
assert.equal(result!.commandId, commandId, `Enters chord for ${commandId} at part ${i}`);
assert.equal(result!.enterChord, false, `Enters chord for ${commandId} at part ${i}`);
} else {
// if it's not the final part, then we should not find a valid command,
// and there should be a chord.
assert.ok(result !== null, `Enters chord for ${commandId} at part ${i}`);
assert.equal(result!.commandId, null, `Enters chord for ${commandId} at part ${i}`);
assert.equal(result!.enterChord, true, `Enters chord for ${commandId} at part ${i}`);
}
previousPart = part;
}
};