本文整理匯總了TypeScript中vs/editor/common/core/range.Range.compareRangesUsingEnds方法的典型用法代碼示例。如果您正苦於以下問題:TypeScript Range.compareRangesUsingEnds方法的具體用法?TypeScript Range.compareRangesUsingEnds怎麽用?TypeScript Range.compareRangesUsingEnds使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類vs/editor/common/core/range.Range
的用法示例。
在下文中一共展示了Range.compareRangesUsingEnds方法的3個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的TypeScript代碼示例。
示例1: _sortOpsDescending
private static _sortOpsDescending(a: IValidatedEditOperation, b: IValidatedEditOperation): number {
let r = Range.compareRangesUsingEnds(a.range, b.range);
if (r === 0) {
return b.sortIndex - a.sortIndex;
}
return -r;
}
示例2: test
test('compareRangesUsingEnds', () => {
let a: Range, b: Range;
a = new Range(1, 1, 1, 3);
b = new Range(1, 2, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) < 0, 'a.start < b.start, a.end < b.end');
a = new Range(1, 1, 1, 3);
b = new Range(1, 1, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) < 0, 'a.start = b.start, a.end < b.end');
a = new Range(1, 2, 1, 3);
b = new Range(1, 1, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) < 0, 'a.start > b.start, a.end < b.end');
a = new Range(1, 1, 1, 4);
b = new Range(1, 2, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) < 0, 'a.start < b.start, a.end = b.end');
a = new Range(1, 1, 1, 4);
b = new Range(1, 1, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) === 0, 'a.start = b.start, a.end = b.end');
a = new Range(1, 2, 1, 4);
b = new Range(1, 1, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) > 0, 'a.start > b.start, a.end = b.end');
a = new Range(1, 1, 1, 5);
b = new Range(1, 2, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) > 0, 'a.start < b.start, a.end > b.end');
a = new Range(1, 1, 2, 4);
b = new Range(1, 1, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) > 0, 'a.start = b.start, a.end > b.end');
a = new Range(1, 1, 5, 1);
b = new Range(1, 1, 1, 4);
assert.ok(Range.compareRangesUsingEnds(a, b) > 0, 'a.start = b.start, a.end > b.end');
});
示例3:
operations = operations.sort((a, b) => -Range.compareRangesUsingEnds(a.range, b.range));