本文整理匯總了TypeScript中tns-core-modules/ui/layouts/stack-layout.StackLayout.insertChild方法的典型用法代碼示例。如果您正苦於以下問題：TypeScript StackLayout.insertChild方法的具體用法？TypeScript StackLayout.insertChild怎麽用？TypeScript StackLayout.insertChild使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類tns-core-modules/ui/layouts/stack-layout.StackLayout的用法示例。
在下文中一共展示了StackLayout.insertChild方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的TypeScript代碼示例。
示例1: test_childNodeInserted_at_index_in_dom_node
export function test_childNodeInserted_at_index_in_dom_node() {
const stack = new StackLayout();
stack.ensureDomNode();
// child index 0
const btn1 = new Button();
btn1.text = "button1";
stack.addChild(btn1);
// child index 1
const btn2 = new Button();
btn2.text = "button2";
stack.addChild(btn2);
// child index 2
const btn3 = new Button();
btn3.text = "button3";
stack.addChild(btn3);
const lbl = new Label();
lbl.text = "label me this";
let called = false;
currentInspector.childNodeInserted = (parentId, lastNodeId, node) => {
assertEqual(lastNodeId, btn1._domId, "Child inserted at index 1's previous sibling does not match.");
assertEqual(JSON.parse(node).nodeId, lbl._domId, "Child id doesn't match");
called = true;
}
stack.insertChild(lbl, 1);
assert(called, "childNodeInserted not called");
}