本文整理匯總了TypeScript中rxjs/operator/withLatestFrom.withLatestFrom.call方法的典型用法代碼示例。如果您正苦於以下問題：TypeScript withLatestFrom.call方法的具體用法？TypeScript withLatestFrom.call怎麽用？TypeScript withLatestFrom.call使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類rxjs/operator/withLatestFrom.withLatestFrom的用法示例。
在下文中一共展示了withLatestFrom.call方法的4個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的TypeScript代碼示例。
示例1: listenForStoreChanges
export function listenForStoreChanges(router: Router, store: Store<any>) {
const storeAndRouter$ = withLatestFrom.call(selectRouter(store), getLatestUrl(router));
const mismatch$ = filter.call(storeAndRouter$, ([ rs, url ]) => rs.path !== url);
const newPath$ = map.call(mismatch$, ([ rs ]) => rs.path);
newPath$.subscribe(url => router.navigateByUrl(url));
}示例2: constructor
constructor(actions$: Dispatcher, state$: State<S>) {
super(1);
withLatestFrom
.call(actions$, state$)
.subscribe(([ action, state ]) => {
super.next({ action, state });
});
}示例3: connectRouterActions
export function connectRouterActions(router: Router, store: Store<any>) {
const routerAndStore$ = withLatestFrom.call(getLatestUrl(router), selectRouter(store));
const mismatchUrl$ = filter.call(routerAndStore$, ([ url, rs ]) => (rs && rs.path !== url || !rs));
const updateLocation$ = map.call(mismatchUrl$, ([ path ]) => {
return { type: routerActions.UPDATE_LOCATION, payload: { path }};
});
updateLocation$.subscribe(store);
}示例4: constructor
constructor(_initialState: T, action$: Dispatcher, reducer$: Reducer) {
super(_initialState);
const actionInQueue$ = observeOn.call(action$, queue);
const actionAndReducer$ = withLatestFrom.call(actionInQueue$, reducer$);
const state$ = scan.call(actionAndReducer$, (state, [ action, reducer ]) => {
return reducer(state, action);
}, _initialState);
state$.subscribe(value => this.next(value));
}