本文整理匯總了TypeScript中property-resolver.PropertyResolver.decomposePropertyRoute方法的典型用法代碼示例。如果您正苦於以下問題：TypeScript PropertyResolver.decomposePropertyRoute方法的具體用法？TypeScript PropertyResolver.decomposePropertyRoute怎麽用？TypeScript PropertyResolver.decomposePropertyRoute使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類property-resolver.PropertyResolver的用法示例。
在下文中一共展示了PropertyResolver.decomposePropertyRoute方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的TypeScript代碼示例。
示例1: it
it('should correctly resolve a property route to a rule', function () {
var rulesetBuilder = new RulesetBuilder();
var nestedRuleset = rulesetBuilder.create()
.forProperty("bar")
.addRule("required", true)
.addRule("maxLength", 10)
.build();
var ruleset = rulesetBuilder.create()
.forProperty("foo")
.addRuleset(nestedRuleset)
.build();
var propertyRoute = "foo.bar";
var ruleResolver = new RuleResolver();
var locatedRules = ruleResolver.resolvePropertyRules(propertyResolver.decomposePropertyRoute(propertyRoute), ruleset);
expect(locatedRules).not.to.be.null;
expect(locatedRules.length).to.equal(2);
expect(locatedRules[0].ruleName).to.equal("required");
expect(locatedRules[0].ruleOptions).to.be.true;
expect(locatedRules[1].ruleName).to.equal("maxLength");
expect(locatedRules[1].ruleOptions).to.equal(10);
});