本文整理匯總了TypeScript中d3-array.bisect函數的典型用法代碼示例。如果您正苦於以下問題：TypeScript bisect函數的具體用法？TypeScript bisect怎麽用？TypeScript bisect使用的例子？那麽, 這裏精選的函數代碼示例或許可以為您提供幫助。
在下文中一共展示了bisect函數的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的TypeScript代碼示例。
示例1: Date
num = d3Array.bisectRight(readonlyNumbersArray, 4);
num = d3Array.bisectRight(readonlyNumbersArray, 4, 1);
num = d3Array.bisectRight(readonlyNumbersArray, 4, 1, 4);
num = d3Array.bisectRight(readonlyStringyNumbersArray, '21');
num = d3Array.bisectRight(readonlyStringyNumbersArray, '21', 1);
num = d3Array.bisectRight(readonlyStringyNumbersArray, '21', 1, 4);
num = d3Array.bisectRight(readonlyDateArray, new Date(2011, 2, 1));
num = d3Array.bisectRight(readonlyDateArray, new Date(2011, 2, 1), 1);
num = d3Array.bisectRight(readonlyDateArray, new Date(2011, 2, 1), 1, 2);
// bisect() --------------------------------------------------------------------
num = d3Array.bisect(numbersArray, 4);
num = d3Array.bisect(numbersArray, 4, 1);
num = d3Array.bisect(numbersArray, 4, 1, 4);
num = d3Array.bisect(stringyNumbersArray, '21');
num = d3Array.bisect(stringyNumbersArray, '21', 1);
num = d3Array.bisect(stringyNumbersArray, '21', 1, 4);
num = d3Array.bisect(dateArray, new Date(2011, 2, 1));
num = d3Array.bisect(dateArray, new Date(2011, 2, 1), 1);
num = d3Array.bisect(dateArray, new Date(2011, 2, 1), 1, 2);
num = d3Array.bisect(typedArray, 4);
num = d3Array.bisect(typedArray, 4, 1);
num = d3Array.bisect(typedArray, 4, 1, 4);
示例2: Date
num = d3Array.bisectRight([0, 2, 3, 4, 7, 8], 4);
num = d3Array.bisectRight([0, 2, 3, 4, 7, 8], 4, 1);
num = d3Array.bisectRight([0, 2, 3, 4, 7, 8], 4, 1, 4);
num = d3Array.bisectRight(['0', '2', '3', '4', '7', '8'], '21');
num = d3Array.bisectRight(['0', '2', '3', '4', '7', '8'], '21', 1);
num = d3Array.bisectRight(['0', '2', '3', '4', '7', '8'], '21', 1, 4);
num = d3Array.bisectRight([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1));
num = d3Array.bisectRight([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1);
num = d3Array.bisectRight([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1, 2);
// bisect() --------------------------------------------------------------------
num = d3Array.bisect([0, 2, 3, 4, 7, 8], 4);
num = d3Array.bisect([0, 2, 3, 4, 7, 8], 4, 1);
num = d3Array.bisect([0, 2, 3, 4, 7, 8], 4, 1, 4);
num = d3Array.bisect(['0', '2', '3', '4', '7', '8'], '21');
num = d3Array.bisect(['0', '2', '3', '4', '7', '8'], '21', 1);
num = d3Array.bisect(['0', '2', '3', '4', '7', '8'], '21', 1, 4);
num = d3Array.bisect([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1));
num = d3Array.bisect([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1);
num = d3Array.bisect([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1, 2);
// bisector() ------------------------------------------------------------------
mixedObjectArray.sort((a, b) => a.date.valueOf() - b.date.valueOf());