本文整理匯總了TypeScript中core/naming.NameUtils.parseClusterName方法的典型用法代碼示例。如果您正苦於以下問題：TypeScript NameUtils.parseClusterName方法的具體用法？TypeScript NameUtils.parseClusterName怎麽用？TypeScript NameUtils.parseClusterName使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類core/naming.NameUtils的用法示例。
在下文中一共展示了NameUtils.parseClusterName方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的TypeScript代碼示例。
示例1: getMatchingRule
public getMatchingRule(
account: string,
location: string,
clusterName: string,
rules: IClusterMatchRule[],
): IClusterMatchRule {
if (!rules || !rules.length) {
return null;
}
const nameParts = NameUtils.parseClusterName(clusterName);
const matchedRules = rules
.filter(r => {
const ruleAccount = r.account || '';
const ruleLocation = r.location || '';
const ruleStack = r.stack || '';
const ruleDetail = r.detail || '';
const stack = nameParts.stack || '';
const detail = nameParts.freeFormDetails || '';
return (
('*' === ruleAccount || account === ruleAccount) &&
('*' === ruleLocation || location === ruleLocation) &&
('*' === ruleStack || stack === ruleStack) &&
('*' === ruleDetail || detail === ruleDetail)
);
})
.sort((a, b) => {
if (a.account !== b.account) {
return a.account === '*' ? 1 : -1;
}
if (a.location !== b.location) {
return a.location === '*' ? 1 : -1;
}
if (a.stack !== b.stack) {
return a.stack === '*' ? 1 : -1;
}
if (a.detail !== b.detail) {
return a.detail === '*' ? 1 : -1;
}
return a.priority - b.priority;
});
return matchedRules.length ? matchedRules[0] : null;
}