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TypeScript O.of方法代碼示例

本文整理匯總了TypeScript中b-o-a.O.of方法的典型用法代碼示例。如果您正苦於以下問題:TypeScript O.of方法的具體用法?TypeScript O.of怎麽用?TypeScript O.of使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在b-o-a.O的用法示例。


在下文中一共展示了O.of方法的7個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的TypeScript代碼示例。

示例1: updater

const prop: PropHandler<Counter> = (
  action$: O<A<any>>,
  state: Counter
): O<Counter> => {
  return O.of<Counter>(state).merge<(state: Counter) => Counter>(
    increment$(action$).map(counter => () => counter)
  ).scan((state: Counter, updater: (state: Counter) => Counter) => {
    return updater(state);
  });
};
開發者ID:boajs,項目名稱:counter-boa,代碼行數:10,代碼來源:counter.ts

示例2: property

export default function property(
  state: string,
  action$: O<A<any>>
): O<string> {
  return O
    .of(state)
    .merge(route$(action$).map(({ route: { name } }) => () => name))
    .scan((state: string, updater: Updater<string>) => {
      return updater(state);
    });
};
開發者ID:bouzuya,項目名稱:rally-rxjs,代碼行數:11,代碼來源:current-page.ts

示例3: property

export default function property(
  state: Token,
  action$: O<A<any>>
): O<Token> {
  return O
    .of(state)
    .merge(reset$(action$).map(token => () => token))
    .scan((state: Token, updater: Updater<Token>) => {
      return updater(state);
    });
};
開發者ID:bouzuya,項目名稱:rally-rxjs,代碼行數:11,代碼來源:token.ts

示例4: property

export default function property(
  state: StampRally,
  action$: O<A<any>>
): O<StampRally> {
  return O
    .of(state)
    .merge(reset$(action$).map(stampRally => () => stampRally))
    .scan((state: StampRally, updater: Updater<StampRally>) => {
      return updater(state);
    });
};
開發者ID:bouzuya,項目名稱:rally-rxjs,代碼行數:11,代碼來源:stamp-rally.ts

示例5: property

export default function property(
  state: Spot[],
  action$: O<A<any>>
): O<Spot[]> {
  return O
    .of(state)
    .merge(reset$(action$).map(spots => () => spots))
    .scan((state: Spot[], updater: Updater<Spot[]>) => {
      return updater(state);
    });
};
開發者ID:bouzuya,項目名稱:rally-rxjs,代碼行數:11,代碼來源:spots.ts

示例6: property

export default function property(
  state: SpotForm,
  action$: O<A<any>>
): O<SpotForm> {
  return O
    .of(state)
    .merge(
    changeName$(action$)
      .map(({ value }) => (state: SpotForm) => {
        return Object.assign({}, state, { name: value });
      })
    )
    .scan((state: SpotForm, updater: Updater<SpotForm>) => {
      return updater(state);
    });
};
開發者ID:bouzuya,項目名稱:rally-rxjs,代碼行數:16,代碼來源:spot-form.ts

示例7: property

export default function property(
  state: SignIn,
  action$: O<A<any>>
): O<SignIn> {
  return O
    .of(state)
    .merge(
      changeEmail$(action$)
        .map(({ value }) => (state: SignIn): SignIn => {
          return Object.assign({}, state, { email: value });
        }),
      changePassword$(action$)
        .map(({ value }) => (state: SignIn): SignIn => {
          return Object.assign({}, state, { password: value });
        }),
      reset$(action$)
        .map(() => (state: SignIn): SignIn => {
          return { email: null, password: null };
        })
    )
    .scan((state: SignIn, updater: Updater<SignIn>) => {
      return updater(state);
    });
};
開發者ID:bouzuya,項目名稱:rally-rxjs,代碼行數:24,代碼來源:sign-in.ts


注:本文中的b-o-a.O.of方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。