本文整理匯總了Python中urllib.request.type方法的典型用法代碼示例。如果您正苦於以下問題:Python request.type方法的具體用法?Python request.type怎麽用?Python request.type使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類urllib.request
的用法示例。
在下文中一共展示了request.type方法的2個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: return_ok_secure
# 需要導入模塊: from urllib import request [as 別名]
# 或者: from urllib.request import type [as 別名]
def return_ok_secure(self, cookie, request):
if cookie.secure and request.type != "https":
_debug(" secure cookie with non-secure request")
return False
return True
示例2: _warcprox_write_record
# 需要導入模塊: from urllib import request [as 別名]
# 或者: from urllib.request import type [as 別名]
def _warcprox_write_record(
self, warcprox_address, url, warc_type, content_type,
payload, extra_headers=None):
headers = {"Content-Type":content_type,"WARC-Type":warc_type,"Host":"N/A"}
if extra_headers:
headers.update(extra_headers)
request = urllib.request.Request(url, method="WARCPROX_WRITE_RECORD",
headers=headers, data=payload)
# XXX setting request.type="http" is a hack to stop urllib from trying
# to tunnel if url is https
request.type = "http"
request.set_proxy(warcprox_address, "http")
try:
with urllib.request.urlopen(request, timeout=600) as response:
if response.getcode() != 204:
self.logger.warning(
'got "%s %s" response on warcprox '
'WARCPROX_WRITE_RECORD request (expected 204)',
response.getcode(), response.reason)
return request, response
except urllib.error.HTTPError as e:
self.logger.warning(
'got "%s %s" response on warcprox '
'WARCPROX_WRITE_RECORD request (expected 204)',
e.getcode(), e.info())
return request, None
except urllib.error.URLError as e:
raise brozzler.ProxyError(
'proxy error on WARCPROX_WRITE_RECORD %s' % url) from e
except ConnectionError as e:
raise brozzler.ProxyError(
'proxy error on WARCPROX_WRITE_RECORD %s' % url) from e