本文整理匯總了Python中tornado.util.re_unescape方法的典型用法代碼示例。如果您正苦於以下問題：Python util.re_unescape方法的具體用法？Python util.re_unescape怎麽用？Python util.re_unescape使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類tornado.util的用法示例。
在下文中一共展示了util.re_unescape方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: _find_groups
# 需要導入模塊: from tornado import util [as 別名]
# 或者: from tornado.util import re_unescape [as 別名]
def _find_groups(self) -> Tuple[Optional[str], Optional[int]]:
"""Returns a tuple (reverse string, group count) for a url.
For example: Given the url pattern /([0-9]{4})/([a-z-]+)/, this method
would return ('/%s/%s/', 2).
"""
pattern = self.regex.pattern
if pattern.startswith("^"):
pattern = pattern[1:]
if pattern.endswith("$"):
pattern = pattern[:-1]
if self.regex.groups != pattern.count("("):
# The pattern is too complicated for our simplistic matching,
# so we can't support reversing it.
return None, None
pieces = []
for fragment in pattern.split("("):
if ")" in fragment:
paren_loc = fragment.index(")")
if paren_loc >= 0:
pieces.append("%s" + fragment[paren_loc + 1 :])
else:
try:
unescaped_fragment = re_unescape(fragment)
except ValueError:
# If we can't unescape part of it, we can't
# reverse this url.
return (None, None)
pieces.append(unescaped_fragment)
return "".join(pieces), self.regex.groups 示例2: _find_groups
# 需要導入模塊: from tornado import util [as 別名]
# 或者: from tornado.util import re_unescape [as 別名]
def _find_groups(url):
"""Returns a tuple (reverse string, group count) for a url.
For example: Given the url pattern /([0-9]{4})/([a-z-]+)/, this method
would return ('/%s/%s/', 2).
"""
regex = re.compile(url)
pattern = url
if pattern.startswith('^'):
pattern = pattern[1:]
if pattern.endswith('$'):
pattern = pattern[:-1]
if regex.groups != pattern.count('('):
# The pattern is too complicated for our simplistic matching,
# so we can't support reversing it.
return None, None
pieces = []
for fragment in pattern.split('('):
if ')' in fragment:
paren_loc = fragment.index(')')
if paren_loc >= 0:
pieces.append('%s' + fragment[paren_loc + 1:])
else:
try:
unescaped_fragment = re_unescape(fragment)
except ValueError:
# If we can't unescape part of it, we can't
# reverse this url.
return (None, None)
pieces.append(unescaped_fragment)
return ''.join(pieces), regex.groups 示例3: _find_groups
# 需要導入模塊: from tornado import util [as 別名]
# 或者: from tornado.util import re_unescape [as 別名]
def _find_groups(self):
"""Returns a tuple (reverse string, group count) for a url.
For example: Given the url pattern /([0-9]{4})/([a-z-]+)/, this method
would return ('/%s/%s/', 2).
"""
pattern = self.regex.pattern
if pattern.startswith('^'):
pattern = pattern[1:]
if pattern.endswith('$'):
pattern = pattern[:-1]
if self.regex.groups != pattern.count('('):
# The pattern is too complicated for our simplistic matching,
# so we can't support reversing it.
return None, None
pieces = []
for fragment in pattern.split('('):
if ')' in fragment:
paren_loc = fragment.index(')')
if paren_loc >= 0:
pieces.append('%s' + fragment[paren_loc + 1:])
else:
try:
unescaped_fragment = re_unescape(fragment)
except ValueError:
# If we can't unescape part of it, we can't
# reverse this url.
return (None, None)
pieces.append(unescaped_fragment)
return ''.join(pieces), self.regex.groups