本文整理匯總了Python中symbol.stmt方法的典型用法代碼示例。如果您正苦於以下問題:Python symbol.stmt方法的具體用法?Python symbol.stmt怎麽用?Python symbol.stmt使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類symbol
的用法示例。
在下文中一共展示了symbol.stmt方法的8個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: Annotate
# 需要導入模塊: import symbol [as 別名]
# 或者: from symbol import stmt [as 別名]
def Annotate(cls, symbol_type, children):
if symbol_type != symbol.stmt:
return None
compound_statement = children[0]
if compound_statement.type != symbol.compound_stmt:
return None
statement = compound_statement.children[0]
if statement.type == symbol.funcdef:
return cls(statement.type, statement.children)
elif (statement.type == symbol.decorated and
statement.children[-1].type == symbol.funcdef):
return cls(statement.type, statement.children)
else:
return None
示例2: Annotate
# 需要導入模塊: import symbol [as 別名]
# 或者: from symbol import stmt [as 別名]
def Annotate(cls, symbol_type, children):
if symbol_type != symbol.stmt:
return None
compound_statement = children[0]
if compound_statement.type != symbol.compound_stmt:
return None
statement = compound_statement.children[0]
if statement.type == symbol.classdef:
return cls(statement.type, statement.children)
elif (statement.type == symbol.decorated and
statement.children[-1].type == symbol.classdef):
return cls(statement.type, statement.children)
else:
return None
示例3: stmt
# 需要導入模塊: import symbol [as 別名]
# 或者: from symbol import stmt [as 別名]
def stmt(self, nodelist):
return self.com_stmt(nodelist[0])
示例4: suite
# 需要導入模塊: import symbol [as 別名]
# 或者: from symbol import stmt [as 別名]
def suite(self, nodelist):
# simple_stmt | NEWLINE INDENT NEWLINE* (stmt NEWLINE*)+ DEDENT
if len(nodelist) == 1:
return self.com_stmt(nodelist[0])
stmts = []
for node in nodelist:
if node[0] == symbol.stmt:
self.com_append_stmt(stmts, node)
return Stmt(stmts)
# --------------------------------------------------------------
#
# EXPRESSION NODES (invoked by com_node())
#
示例5: com_node
# 需要導入模塊: import symbol [as 別名]
# 或者: from symbol import stmt [as 別名]
def com_node(self, node):
# Note: compile.c has handling in com_node for del_stmt, pass_stmt,
# break_stmt, stmt, small_stmt, flow_stmt, simple_stmt,
# and compound_stmt.
# We'll just dispatch them.
return self._dispatch[node[0]](node[1:])
示例6: get_docstring
# 需要導入模塊: import symbol [as 別名]
# 或者: from symbol import stmt [as 別名]
def get_docstring(self, node, n=None):
if n is None:
n = node[0]
node = node[1:]
if n == symbol.suite:
if len(node) == 1:
return self.get_docstring(node[0])
for sub in node:
if sub[0] == symbol.stmt:
return self.get_docstring(sub)
return None
if n == symbol.file_input:
for sub in node:
if sub[0] == symbol.stmt:
return self.get_docstring(sub)
return None
if n == symbol.atom:
if node[0][0] == token.STRING:
s = ''
for t in node:
s = s + eval(t[1])
return s
return None
if n == symbol.stmt or n == symbol.simple_stmt \
or n == symbol.small_stmt:
return self.get_docstring(node[0])
if n in _doc_nodes and len(node) == 1:
return self.get_docstring(node[0])
return None
示例7: analyze_morf
# 需要導入模塊: import symbol [as 別名]
# 或者: from symbol import stmt [as 別名]
def analyze_morf(self, morf):
if self.analysis_cache.has_key(morf):
return self.analysis_cache[morf]
filename = self.morf_filename(morf)
ext = os.path.splitext(filename)[1]
if ext == '.pyc':
if not os.path.exists(filename[0:-1]):
raise self.error, ("No source for compiled code '%s'."
% filename)
filename = filename[0:-1]
elif ext != '.py':
raise self.error, "File '%s' not Python source." % filename
source = open(filename, 'r')
import parser
tree = parser.suite(source.read()).totuple(1)
source.close()
statements = {}
self.find_statements(tree, statements)
lines = statements.keys()
lines.sort()
result = filename, lines
self.analysis_cache[morf] = result
return result
# find_statements(tree, dict). Find each statement in the parse
# tree and record the line on which the statement starts in the
# dictionary (by assigning it to 1).
#
# It works by walking the whole tree depth-first. Every time it
# comes across a statement (symbol.stmt -- this includes compound
# statements like 'if' and 'while') it calls find_statement, which
# descends the tree below the statement to find the first terminal
# token in that statement and record the lines on which that token
# was found.
#
# This algorithm may find some lines several times (because of the
# grammar production statement -> compound statement -> statement),
# but that doesn't matter because we record lines as the keys of the
# dictionary.
#
# See also [GDR 2001-12-04b, 3.2].
示例8: find_statements
# 需要導入模塊: import symbol [as 別名]
# 或者: from symbol import stmt [as 別名]
def find_statements(self, tree, dict):
import symbol, token
if token.ISNONTERMINAL(tree[0]):
for t in tree[1:]:
self.find_statements(t, dict)
if tree[0] == symbol.stmt:
self.find_statement(tree[1], dict)
elif (tree[0] == token.NAME
and tree[1] in ['elif', 'except', 'finally']):
dict[tree[2]] = 1