本文整理匯總了Python中string.pyc方法的典型用法代碼示例。如果您正苦於以下問題：Python string.pyc方法的具體用法？Python string.pyc怎麽用？Python string.pyc使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類string的用法示例。
在下文中一共展示了string.pyc方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: _get_codename
# 需要導入模塊: import string [as 別名]
# 或者: from string import pyc [as 別名]
def _get_codename(self, pathname, basename):
"""Return (filename, archivename) for the path.
Given a module name path, return the correct file path and
archive name, compiling if necessary. For example, given
/python/lib/string, return (/python/lib/string.pyc, string).
"""
file_py = pathname + ".py"
file_pyc = pathname + ".pyc"
file_pyo = pathname + ".pyo"
if os.path.isfile(file_pyo) and \
os.stat(file_pyo).st_mtime >= os.stat(file_py).st_mtime:
fname = file_pyo # Use .pyo file
elif not os.path.isfile(file_pyc) or \
os.stat(file_pyc).st_mtime < os.stat(file_py).st_mtime:
import py_compile
if self.debug:
print "Compiling", file_py
try:
py_compile.compile(file_py, file_pyc, None, True)
except py_compile.PyCompileError,err:
print err.msg
fname = file_pyc 示例2: _get_codename
# 需要導入模塊: import string [as 別名]
# 或者: from string import pyc [as 別名]
def _get_codename(self, pathname, basename):
"""Return (filename, archivename) for the path.
Given a module name path, return the correct file path and
archive name, compiling if necessary. For example, given
/python/lib/string, return (/python/lib/string.pyc, string).
"""
file_py = pathname + ".py"
file_pyc = pathname + ".pyc"
file_pyo = pathname + ".pyo"
if os.path.isfile(file_pyo) and \
os.stat(file_pyo).st_mtime >= os.stat(file_py).st_mtime:
fname = file_pyo # Use .pyo file
elif not os.path.isfile(file_pyc) or \
os.stat(file_pyc).st_mtime < os.stat(file_py).st_mtime:
import py_compile
if self.debug:
print("Compiling", file_py)
try:
py_compile.compile(file_py, file_pyc, None, True)
except py_compile.PyCompileError as err:
print(err.msg)
fname = file_pyc
else:
fname = file_pyc
archivename = os.path.split(fname)[1]
if basename:
archivename = "%s/%s" % (basename, archivename)
return (fname, archivename) 示例3: _get_codename
# 需要導入模塊: import string [as 別名]
# 或者: from string import pyc [as 別名]
def _get_codename(self, pathname, basename):
"""Return (filename, archivename) for the path.
Given a module name path, return the correct file path and
archive name, compiling if necessary. For example, given
/python/lib/string, return (/python/lib/string.pyc, string).
"""
file_py = pathname + ".py"
if _is_jython:
import imp
file_pyc = imp._makeCompiledFilename(file_py)
else:
file_pyc = pathname + ".pyc"
file_pyo = pathname + ".pyo"
if os.path.isfile(file_pyo) and \
os.stat(file_pyo).st_mtime >= os.stat(file_py).st_mtime:
fname = file_pyo # Use .pyo file
elif not os.path.isfile(file_pyc) or \
os.stat(file_pyc).st_mtime < os.stat(file_py).st_mtime:
import py_compile
if self.debug:
print "Compiling", file_py
try:
py_compile.compile(file_py, file_pyc, None, True)
except py_compile.PyCompileError,err:
print err.msg
fname = file_pyc