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Python pyparsing.NoMatch方法代碼示例

本文整理匯總了Python中pyparsing.NoMatch方法的典型用法代碼示例。如果您正苦於以下問題:Python pyparsing.NoMatch方法的具體用法?Python pyparsing.NoMatch怎麽用?Python pyparsing.NoMatch使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在pyparsing的用法示例。


在下文中一共展示了pyparsing.NoMatch方法的2個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: _make_matcher_element

# 需要導入模塊: import pyparsing [as 別名]
# 或者: from pyparsing import NoMatch [as 別名]
def _make_matcher_element(self):
        return self._set_matcher_element_attributes(pyparsing.NoMatch()) 
開發者ID:Danesprite,項目名稱:pyjsgf,代碼行數:4,代碼來源:expansions.py

示例2: _make_matcher_element

# 需要導入模塊: import pyparsing [as 別名]
# 或者: from pyparsing import NoMatch [as 別名]
def _make_matcher_element(self):
        # Handle the case where use_current_match is True.
        if self.use_current_match is True:
            current_match = self.current_match
            if current_match is None:
                result = pyparsing.NoMatch()
            elif current_match == "":
                result = pyparsing.Empty()
            else:
                result = pyparsing.Literal(self.current_match)

            # Set the parse action and return the element.
            return result.setParseAction(self._parse_action)

        # Otherwise build a list of next possible literals. Make the required stack
        # of child-parent pairs.
        stack = []
        p1, p2 = self, self.parent
        while p1 and p2:
            stack.append((p1, p2))

            # Move both pivots further up the tree.
            p1 = p1.parent
            p2 = p2.parent

        # Build a list of next literals using the stack.
        next_literals, _ = _collect_next_literals(stack, 0, True, False)

        # De-duplicate the list.
        next_literals = set(next_literals)

        word = pyparsing.Regex(_word_regex_str, re.UNICODE)
        if next_literals:
            # Check if there is a next dictation literal. If there is, only match
            # one word for this expansion.
            if _word_regex_str in next_literals:
                result = word

            # Otherwise build an element to match one or more words stopping on
            # any of the next literals so that they aren't matched as dictation.
            else:
                next_literals = list(map(pyparsing.Literal, next_literals))
                result = pyparsing.OneOrMore(
                    word, stopOn=pyparsing.Or(next_literals)
                )
        else:
            # Handle the case of no literals ahead by allowing one or more Unicode
            # words without restrictions.
            result = pyparsing.OneOrMore(word)

        return self._set_matcher_element_attributes(result) 
開發者ID:Danesprite,項目名稱:pyjsgf,代碼行數:53,代碼來源:expansions.py


注:本文中的pyparsing.NoMatch方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。