本文整理匯總了Python中pip._internal.utils.packaging.check_requires_python方法的典型用法代碼示例。如果您正苦於以下問題：Python packaging.check_requires_python方法的具體用法？Python packaging.check_requires_python怎麽用？Python packaging.check_requires_python使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類pip._internal.utils.packaging的用法示例。
在下文中一共展示了packaging.check_requires_python方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: _check_link_requires_python
# 需要導入模塊: from pip._internal.utils import packaging [as 別名]
# 或者: from pip._internal.utils.packaging import check_requires_python [as 別名]
def _check_link_requires_python(
link, # type: Link
version_info, # type: Tuple[int, int, int]
ignore_requires_python=False, # type: bool
):
# type: (...) -> bool
"""
Return whether the given Python version is compatible with a link's
"Requires-Python" value.
:param version_info: A 3-tuple of ints representing the Python
major-minor-micro version to check.
:param ignore_requires_python: Whether to ignore the "Requires-Python"
value if the given Python version isn't compatible.
"""
try:
is_compatible = check_requires_python(
link.requires_python, version_info=version_info,
)
except specifiers.InvalidSpecifier:
logger.debug(
"Ignoring invalid Requires-Python (%r) for link: %s",
link.requires_python, link,
)
else:
if not is_compatible:
version = '.'.join(map(str, version_info))
if not ignore_requires_python:
logger.debug(
'Link requires a different Python (%s not in: %r): %s',
version, link.requires_python, link,
)
return False
logger.debug(
'Ignoring failed Requires-Python check (%s not in: %r) '
'for link: %s',
version, link.requires_python, link,
)
return True