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Python pickle.py方法代碼示例

本文整理匯總了Python中pickle.py方法的典型用法代碼示例。如果您正苦於以下問題:Python pickle.py方法的具體用法?Python pickle.py怎麽用?Python pickle.py使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在pickle的用法示例。


在下文中一共展示了pickle.py方法的3個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: test_cyclic_memoize

# 需要導入模塊: import pickle [as 別名]
# 或者: from pickle import py [as 別名]
def test_cyclic_memoize(self):
        # http://bugs.python.org/issue998998 - cPickle shouldn't fail
        # this, though pickle.py still does
        m = MyClass()
        m2 = MyClass()

        s = set([m])
        m.foo = set([m2])
        m2.foo = s

        s2 = cPickle.loads(cPickle.dumps(s))
        self.assertEqual(len(s2), 1)
        m3 = iter(s2).next()
        self.assertEqual(len(m3.foo), 1)
        m4 = iter(m3.foo).next()
        self.assertEqual(m4.foo, s2) 
開發者ID:ofermend,項目名稱:medicare-demo,代碼行數:18,代碼來源:test_cpickle_jy.py

示例2: assure_pickle_consistency

# 需要導入模塊: import pickle [as 別名]
# 或者: from pickle import py [as 別名]
def assure_pickle_consistency(verbose=False):
    import pickle, re

    copy = code2op.copy()
    for name in pickle.__all__:
        if not re.match("[A-Z][A-Z0-9_]+$", name):
            if verbose:
                print "skipping %r: it doesn't look like an opcode name" % name
            continue
        picklecode = getattr(pickle, name)
        if not isinstance(picklecode, str) or len(picklecode) != 1:
            if verbose:
                print ("skipping %r: value %r doesn't look like a pickle "
                       "code" % (name, picklecode))
            continue
        if picklecode in copy:
            if verbose:
                print "checking name %r w/ code %r for consistency" % (
                      name, picklecode)
            d = copy[picklecode]
            if d.name != name:
                raise ValueError("for pickle code %r, pickle.py uses name %r "
                                 "but we're using name %r" % (picklecode,
                                                              name,
                                                              d.name))
            # Forget this one.  Any left over in copy at the end are a problem
            # of a different kind.
            del copy[picklecode]
        else:
            raise ValueError("pickle.py appears to have a pickle opcode with "
                             "name %r and code %r, but we don't" %
                             (name, picklecode))
    if copy:
        msg = ["we appear to have pickle opcodes that pickle.py doesn't have:"]
        for code, d in copy.items():
            msg.append("    name %r with code %r" % (d.name, code))
        raise ValueError("\n".join(msg)) 
開發者ID:glmcdona,項目名稱:meddle,代碼行數:39,代碼來源:pickletools.py

示例3: assure_pickle_consistency

# 需要導入模塊: import pickle [as 別名]
# 或者: from pickle import py [as 別名]
def assure_pickle_consistency(verbose=False):

    copy = code2op.copy()
    for name in pickle.__all__:
        if not re.match("[A-Z][A-Z0-9_]+$", name):
            if verbose:
                print("skipping %r: it doesn't look like an opcode name" % name)
            continue
        picklecode = getattr(pickle, name)
        if not isinstance(picklecode, bytes) or len(picklecode) != 1:
            if verbose:
                print(("skipping %r: value %r doesn't look like a pickle "
                       "code" % (name, picklecode)))
            continue
        picklecode = picklecode.decode("latin-1")
        if picklecode in copy:
            if verbose:
                print("checking name %r w/ code %r for consistency" % (
                      name, picklecode))
            d = copy[picklecode]
            if d.name != name:
                raise ValueError("for pickle code %r, pickle.py uses name %r "
                                 "but we're using name %r" % (picklecode,
                                                              name,
                                                              d.name))
            # Forget this one.  Any left over in copy at the end are a problem
            # of a different kind.
            del copy[picklecode]
        else:
            raise ValueError("pickle.py appears to have a pickle opcode with "
                             "name %r and code %r, but we don't" %
                             (name, picklecode))
    if copy:
        msg = ["we appear to have pickle opcodes that pickle.py doesn't have:"]
        for code, d in copy.items():
            msg.append("    name %r with code %r" % (d.name, code))
        raise ValueError("\n".join(msg)) 
開發者ID:Microvellum,項目名稱:Fluid-Designer,代碼行數:39,代碼來源:pickletools.py


注:本文中的pickle.py方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。