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Python sorting.is_int64_overflow_possible方法代碼示例

本文整理匯總了Python中pandas.core.sorting.is_int64_overflow_possible方法的典型用法代碼示例。如果您正苦於以下問題:Python sorting.is_int64_overflow_possible方法的具體用法?Python sorting.is_int64_overflow_possible怎麽用?Python sorting.is_int64_overflow_possible使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在pandas.core.sorting的用法示例。


在下文中一共展示了sorting.is_int64_overflow_possible方法的2個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: _get_join_keys

# 需要導入模塊: from pandas.core import sorting [as 別名]
# 或者: from pandas.core.sorting import is_int64_overflow_possible [as 別名]
def _get_join_keys(llab, rlab, shape, sort):

    # how many levels can be done without overflow
    pred = lambda i: not is_int64_overflow_possible(shape[:i])
    nlev = next(filter(pred, range(len(shape), 0, -1)))

    # get keys for the first `nlev` levels
    stride = np.prod(shape[1:nlev], dtype='i8')
    lkey = stride * llab[0].astype('i8', subok=False, copy=False)
    rkey = stride * rlab[0].astype('i8', subok=False, copy=False)

    for i in range(1, nlev):
        with np.errstate(divide='ignore'):
            stride //= shape[i]
        lkey += llab[i] * stride
        rkey += rlab[i] * stride

    if nlev == len(shape):  # all done!
        return lkey, rkey

    # densify current keys to avoid overflow
    lkey, rkey, count = _factorize_keys(lkey, rkey, sort=sort)

    llab = [lkey] + llab[nlev:]
    rlab = [rkey] + rlab[nlev:]
    shape = [count] + shape[nlev:]

    return _get_join_keys(llab, rlab, shape, sort) 
開發者ID:Frank-qlu,項目名稱:recruit,代碼行數:30,代碼來源:merge.py

示例2: _get_join_keys

# 需要導入模塊: from pandas.core import sorting [as 別名]
# 或者: from pandas.core.sorting import is_int64_overflow_possible [as 別名]
def _get_join_keys(llab, rlab, shape, sort):

    # how many levels can be done without overflow
    pred = lambda i: not is_int64_overflow_possible(shape[:i])
    nlev = next(filter(pred, range(len(shape), 0, -1)))

    # get keys for the first `nlev` levels
    stride = np.prod(shape[1:nlev], dtype='i8')
    lkey = stride * llab[0].astype('i8', subok=False, copy=False)
    rkey = stride * rlab[0].astype('i8', subok=False, copy=False)

    for i in range(1, nlev):
        stride //= shape[i]
        lkey += llab[i] * stride
        rkey += rlab[i] * stride

    if nlev == len(shape):  # all done!
        return lkey, rkey

    # densify current keys to avoid overflow
    lkey, rkey, count = _factorize_keys(lkey, rkey, sort=sort)

    llab = [lkey] + llab[nlev:]
    rlab = [rkey] + rlab[nlev:]
    shape = [count] + shape[nlev:]

    return _get_join_keys(llab, rlab, shape, sort) 
開發者ID:securityclippy,項目名稱:elasticintel,代碼行數:29,代碼來源:merge.py


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