本文整理匯總了Python中pandas.Timestamp.fromordinal方法的典型用法代碼示例。如果您正苦於以下問題：Python Timestamp.fromordinal方法的具體用法？Python Timestamp.fromordinal怎麽用？Python Timestamp.fromordinal使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類pandas.Timestamp的用法示例。
在下文中一共展示了Timestamp.fromordinal方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: test_constructor_fromordinal
# 需要導入模塊: from pandas import Timestamp [as 別名]
# 或者: from pandas.Timestamp import fromordinal [as 別名]
def test_constructor_fromordinal(self):
base = datetime(2000, 1, 1)
ts = Timestamp.fromordinal(base.toordinal(), freq='D')
assert base == ts
assert ts.freq == 'D'
assert base.toordinal() == ts.toordinal()
ts = Timestamp.fromordinal(base.toordinal(), tz='US/Eastern')
assert Timestamp('2000-01-01', tz='US/Eastern') == ts
assert base.toordinal() == ts.toordinal()
# GH#3042
dt = datetime(2011, 4, 16, 0, 0)
ts = Timestamp.fromordinal(dt.toordinal())
assert ts.to_pydatetime() == dt
# with a tzinfo
stamp = Timestamp('2011-4-16', tz='US/Eastern')
dt_tz = stamp.to_pydatetime()
ts = Timestamp.fromordinal(dt_tz.toordinal(), tz='US/Eastern')
assert ts.to_pydatetime() == dt_tz 示例2: simulate
# 需要導入模塊: from pandas import Timestamp [as 別名]
# 或者: from pandas.Timestamp import fromordinal [as 別名]
def simulate(self, p, tmin=None, tmax=None, freq=None, dt=1):
tindex = date_range(tmin, tmax, freq=freq)
if p[1] < tindex[0].toordinal():
tmin = tindex[0]
else:
tmin = Timestamp.fromordinal(int(p[1]))
if p[2] >= tindex[-1].toordinal():
tmax = tindex[-1]
else:
tmax = Timestamp.fromordinal(int(p[2]))
trend = tindex.to_series().diff() / Timedelta(1, "D")
trend.loc[:tmin] = 0
trend.loc[tmax:] = 0
trend = trend.cumsum() * p[0]
return trend