本文整理匯總了Python中google.appengine.api.urlfetch.ResponseTooLargeError方法的典型用法代碼示例。如果您正苦於以下問題：Python urlfetch.ResponseTooLargeError方法的具體用法？Python urlfetch.ResponseTooLargeError怎麽用？Python urlfetch.ResponseTooLargeError使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類google.appengine.api.urlfetch的用法示例。
在下文中一共展示了urlfetch.ResponseTooLargeError方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: _handle_request_error
# 需要導入模塊: from google.appengine.api import urlfetch [as 別名]
# 或者: from google.appengine.api.urlfetch import ResponseTooLargeError [as 別名]
def _handle_request_error(self, e, url):
if isinstance(e, urlfetch.InvalidURLError):
msg = ("The Stripe library attempted to fetch an "
"invalid URL (%r). This is likely due to a bug "
"in the Stripe Python bindings. Please let us know "
"at support@stripe.com." % (url,))
elif isinstance(e, urlfetch.DownloadError):
msg = "There was a problem retrieving data from Stripe."
elif isinstance(e, urlfetch.ResponseTooLargeError):
msg = ("There was a problem receiving all of your data from "
"Stripe. This is likely due to a bug in Stripe. "
"Please let us know at support@stripe.com.")
else:
msg = ("Unexpected error communicating with Stripe. If this "
"problem persists, let us know at support@stripe.com.")
msg = textwrap.fill(msg) + "\n\n(Network error: " + str(e) + ")"
raise error.APIConnectionError(msg) 示例2: _handle_request_error
# 需要導入模塊: from google.appengine.api import urlfetch [as 別名]
# 或者: from google.appengine.api.urlfetch import ResponseTooLargeError [as 別名]
def _handle_request_error(self, e, url):
if isinstance(e, urlfetch.InvalidURLError):
msg = ("The Shippo library attempted to fetch an "
"invalid URL (%r). This is likely due to a bug "
"in the Shippo Python bindings. Please let us know "
"at support@goshippo.com." % (url,))
elif isinstance(e, urlfetch.DownloadError):
msg = "There was a problem retrieving data from Shippo."
elif isinstance(e, urlfetch.ResponseTooLargeError):
msg = ("There was a problem receiving all of your data from "
"Shippo. This is likely due to a bug in Shippo. "
"Please let us know at support@goshippo.com.")
else:
msg = ("Unexpected error communicating with Shippo. If this "
"problem persists, let us know at support@goshippo.com.")
msg = textwrap.fill(msg) + "\n\n(Network error: " + str(e) + ")"
raise error.APIConnectionError(msg)