Python subqueries.AggregateQuery方法代碼示例

# 需要導入模塊: from django.db.models.sql import subqueries [as 別名]
# 或者: from django.db.models.sql.subqueries import AggregateQuery [as 別名]
def get_count(self, using):
        """
        Performs a COUNT() query using the current filter constraints.
        """
        obj = self.clone()
        if len(self.select) > 1 or self.aggregate_select or (self.distinct and self.distinct_fields):
            # If a select clause exists, then the query has already started to
            # specify the columns that are to be returned.
            # In this case, we need to use a subquery to evaluate the count.
            from django.db.models.sql.subqueries import AggregateQuery
            subquery = obj
            subquery.clear_ordering(True)
            subquery.clear_limits()

            obj = AggregateQuery(obj.model)
            try:
                obj.add_subquery(subquery, using=using)
            except EmptyResultSet:
                # add_subquery evaluates the query, if it's an EmptyResultSet
                # then there are can be no results, and therefore there the
                # count is obviously 0
                return 0

        obj.add_count_column()
        number = obj.get_aggregation(using=using)[None]

        # Apply offset and limit constraints manually, since using LIMIT/OFFSET
        # in SQL (in variants that provide them) doesn't change the COUNT
        # output.
        number = max(0, number - self.low_mark)
        if self.high_mark is not None:
            number = min(number, self.high_mark - self.low_mark)

        return number 

# 需要導入模塊: from django.db.models.sql import subqueries [as 別名]
# 或者: from django.db.models.sql.subqueries import AggregateQuery [as 別名]
def get_aggregation(self, using):
        """
        Returns the dictionary with the values of the existing aggregations.
        """
        if not self.aggregate_select:
            return {}

        # If there is a group by clause, aggregating does not add useful
        # information but retrieves only the first row. Aggregate
        # over the subquery instead.
        if self.group_by is not None:
            from django.db.models.sql.subqueries import AggregateQuery
            query = AggregateQuery(self.model)

            obj = self.clone()

            # Remove any aggregates marked for reduction from the subquery
            # and move them to the outer AggregateQuery.
            for alias, aggregate in self.aggregate_select.items():
                if aggregate.is_summary:
                    query.aggregate_select[alias] = aggregate
                    del obj.aggregate_select[alias]

            try:
                query.add_subquery(obj, using)
            except EmptyResultSet:
                return dict(
                    (alias, None)
                    for alias in query.aggregate_select
                )
        else:
            query = self
            self.select = []
            self.default_cols = False
            self.extra = {}
            self.remove_inherited_models()

        query.clear_ordering(True)
        query.clear_limits()
        query.select_for_update = False
        query.select_related = False
        query.related_select_cols = []
        query.related_select_fields = []

        result = query.get_compiler(using).execute_sql(SINGLE)
        if result is None:
            result = [None for q in query.aggregate_select.items()]

        return dict([
            (alias, self.resolve_aggregate(val, aggregate, connection=connections[using]))
            for (alias, aggregate), val
            in zip(query.aggregate_select.items(), result)
        ])