Python query.get_order_dir方法代碼示例

# 需要導入模塊: from django.db.models.sql import query [as 別名]
# 或者: from django.db.models.sql.query import get_order_dir [as 別名]
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.rel and path and opts.ordering and name != field.attname:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(self.query.alias_map[j].table_name for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets] 

# 需要導入模塊: from django.db.models.sql import query [as 別名]
# 或者: from django.db.models.sql.query import get_order_dir [as 別名]
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Return the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets] 

# 需要導入模塊: from django.db.models.sql import query [as 別名]
# 或者: from django.db.models.sql.query import get_order_dir [as 別名]
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Return the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = order == 'DESC'
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts, transform_function = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            already_seen = already_seen or set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(transform_function(t, alias), descending=descending), False) for t in targets] 

# 需要導入模塊: from django.db.models.sql import query [as 別名]
# 或者: from django.db.models.sql.query import get_order_dir [as 別名]
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets] 

# 需要導入模塊: from django.db.models.sql import query [as 別名]
# 或者: from django.db.models.sql.query import get_order_dir [as 別名]
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
            already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        pieces = name.split(LOOKUP_SEP)
        field, col, alias, joins, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model.
        if field.rel and len(joins) > 1 and opts.ordering:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple([self.query.alias_map[j].table_name for j in joins])
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                        order, already_seen))
            return results
        col, alias = self._final_join_removal(col, alias)
        return [(alias, col, order)] 

# 需要導入模塊: from django.db.models.sql import query [as 別名]
# 或者: from django.db.models.sql.query import get_order_dir [as 別名]
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and path and opts.ordering and name != field.attname:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets]