本文整理匯總了Python中django.contrib.auth.views.password_change方法的典型用法代碼示例。如果您正苦於以下問題：Python views.password_change方法的具體用法？Python views.password_change怎麽用？Python views.password_change使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類django.contrib.auth.views的用法示例。
在下文中一共展示了views.password_change方法的4個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: password_change
# 需要導入模塊: from django.contrib.auth import views [as 別名]
# 或者: from django.contrib.auth.views import password_change [as 別名]
def password_change(self, request, extra_context=None):
"""
Handles the "change password" task -- both form display and validation.
"""
from django.contrib.admin.forms import AdminPasswordChangeForm
from django.contrib.auth.views import password_change
url = reverse('admin:password_change_done', current_app=self.name)
defaults = {
'current_app': self.name,
'password_change_form': AdminPasswordChangeForm,
'post_change_redirect': url,
'extra_context': dict(self.each_context(request), **(extra_context or {})),
}
if self.password_change_template is not None:
defaults['template_name'] = self.password_change_template
return password_change(request, **defaults) 示例2: password_change
# 需要導入模塊: from django.contrib.auth import views [as 別名]
# 或者: from django.contrib.auth.views import password_change [as 別名]
def password_change(self, request, extra_context=None):
"""
Handles the "change password" task -- both form display and validation.
"""
from django.contrib.admin.forms import AdminPasswordChangeForm
from django.contrib.auth.views import password_change
url = reverse('admin:password_change_done', current_app=self.name)
defaults = {
'password_change_form': AdminPasswordChangeForm,
'post_change_redirect': url,
'extra_context': dict(self.each_context(request), **(extra_context or {})),
}
if self.password_change_template is not None:
defaults['template_name'] = self.password_change_template
request.current_app = self.name
return password_change(request, **defaults) 示例3: get_urls
# 需要導入模塊: from django.contrib.auth import views [as 別名]
# 或者: from django.contrib.auth.views import password_change [as 別名]
def get_urls(self):
from django.conf.urls import url, include
# Since this module gets imported in the application's root package,
# it cannot import models from other applications at the module level,
# and django.contrib.contenttypes.views imports ContentType.
from django.contrib.contenttypes import views as contenttype_views
if settings.DEBUG:
self.check_dependencies()
def wrap(view, cacheable=False):
def wrapper(*args, **kwargs):
return self.admin_view(view, cacheable)(*args, **kwargs)
return update_wrapper(wrapper, view)
# Admin-site-wide views.
urlpatterns = [
url(r'^$', wrap(self.index), name='index'),
url(r'^login/$', self.login, name='login'),
url(r'^logout/$', wrap(self.logout), name='logout'),
url(r'^password_change/$', wrap(self.password_change, cacheable=True), name='password_change'),
url(r'^password_change/done/$', wrap(self.password_change_done, cacheable=True),
name='password_change_done'),
url(r'^jsi18n/$', wrap(self.i18n_javascript, cacheable=True), name='jsi18n'),
url(r'^r/(?P<content_type_id>\d+)/(?P<object_id>.+)/$', wrap(contenttype_views.shortcut),
name='view_on_site'),
]
# Add in each model's views, and create a list of valid URLS for the
# app_index
valid_app_labels = []
for model, model_admin in six.iteritems(self._registry):
urlpatterns += [
url(r'^%s/%s/' % (model._meta.app_label, model._meta.model_name), include(model_admin.urls)),
]
if model._meta.app_label not in valid_app_labels:
valid_app_labels.append(model._meta.app_label)
# If there were ModelAdmins registered, we should have a list of app
# labels for which we need to allow access to the app_index view,
if valid_app_labels:
regex = r'^(?P<app_label>' + '|'.join(valid_app_labels) + ')/$'
urlpatterns += [
url(regex, wrap(self.app_index), name='app_list'),
]
return urlpatterns 示例4: get_urls
# 需要導入模塊: from django.contrib.auth import views [as 別名]
# 或者: from django.contrib.auth.views import password_change [as 別名]
def get_urls(self):
from django.conf.urls import url, include
# Since this module gets imported in the application's root package,
# it cannot import models from other applications at the module level,
# and django.contrib.contenttypes.views imports ContentType.
from django.contrib.contenttypes import views as contenttype_views
if settings.DEBUG:
self.check_dependencies()
def wrap(view, cacheable=False):
def wrapper(*args, **kwargs):
return self.admin_view(view, cacheable)(*args, **kwargs)
wrapper.admin_site = self
return update_wrapper(wrapper, view)
# Admin-site-wide views.
urlpatterns = [
url(r'^$', wrap(self.index), name='index'),
url(r'^login/$', self.login, name='login'),
url(r'^logout/$', wrap(self.logout), name='logout'),
url(r'^password_change/$', wrap(self.password_change, cacheable=True), name='password_change'),
url(r'^password_change/done/$', wrap(self.password_change_done, cacheable=True),
name='password_change_done'),
url(r'^jsi18n/$', wrap(self.i18n_javascript, cacheable=True), name='jsi18n'),
url(r'^r/(?P<content_type_id>\d+)/(?P<object_id>.+)/$', wrap(contenttype_views.shortcut),
name='view_on_site'),
]
# Add in each model's views, and create a list of valid URLS for the
# app_index
valid_app_labels = []
for model, model_admin in self._registry.items():
urlpatterns += [
url(r'^%s/%s/' % (model._meta.app_label, model._meta.model_name), include(model_admin.urls)),
]
if model._meta.app_label not in valid_app_labels:
valid_app_labels.append(model._meta.app_label)
# If there were ModelAdmins registered, we should have a list of app
# labels for which we need to allow access to the app_index view,
if valid_app_labels:
regex = r'^(?P<app_label>' + '|'.join(valid_app_labels) + ')/$'
urlpatterns += [
url(regex, wrap(self.app_index), name='app_list'),
]
return urlpatterns