Python cupy.dot方法代碼示例

# 需要導入模塊: import cupy [as 別名]
# 或者: from cupy import dot [as 別名]
def apply_mapping(x, model_params, src='src', tgt='tgt', latent_space=True): 
    """
     Applies bilingual mapping to the matrix x and returns the transformed matrix. 
     
     vocab_type is one of `src` or `tgt`. Indicates the source or target language as per the trained model. 

     latent_space: If true, the embeddings are mapped to latent space. Otherwise, 
        they are mapped to the embedding space of the other language. 
    """
   
    xw=None 

    src_mat_name='U_{}'.format(src)
    tgt_mat_name='U_{}'.format(tgt)
    
    if latent_space:
        xw = x.dot( model_params[src_mat_name] ).dot(scipy.linalg.sqrtm( model_params['B']  ))
    else:
        xw = x.dot( model_params[src_mat_name] ).dot( model_params['B'] ).dot( model_params[tgt_mat_name].T )   
    
    return xw 

# 需要導入模塊: import cupy [as 別名]
# 或者: from cupy import dot [as 別名]
def compute_word_similarity(emb_info, sim_database):
            
    emb_words, emb_vectors = emb_info
    w2i=build_w2i(emb_info[0])
    
    sim_words = set([ x[0] for x in sim_database ])
    sim_words.update([ x[1] for x in sim_database ])
    oov_words = sim_words.difference(emb_words)
    non_oov_words=sim_words.difference(oov_words)
    
    non_oov_sim_pairs = list(filter( lambda x: len(oov_words.intersection(x[:2]))==0 , sim_database))

    cos_sims=[]
    ref_sims=[]
    
    for w1, w2, ref_sim in non_oov_sim_pairs:
        v1=emb_vectors[w2i[w1]]
        v2=emb_vectors[w2i[w2]]
        cos_sim=np.dot(v1,v2)/np.sqrt(v1.dot(v1)*v2.dot(v2))
        
        cos_sims.append(cos_sim)
        ref_sims.append(ref_sim)
    
    corr=scipy.stats.spearmanr(np.array(cos_sims),np.array(ref_sims))
    return corr[0], corr[1], len(non_oov_sim_pairs)/len(sim_database) 

# 需要導入模塊: import cupy [as 別名]
# 或者: from cupy import dot [as 別名]
def test_01(self):
        N = 64
        K = 5
        L = 10
        u = cp.random.randn(N, K)
        U = cp.dot(u, u.T)
        V = cp.random.randn(N, N)
        t = cp.sort(cp.abs(V).ravel())[V.size-L]
        V[cp.abs(V) < t] = 0
        D = U + V
        opt = rpca.RobustPCA.Options({'Verbose': False, 'gEvalY': False,
                                      'MaxMainIter': 250,
                                      'AutoRho': {'Enabled': True}})
        b = rpca.RobustPCA(D, None, opt)
        X, Y = b.solve()
        assert sm.mse(U, X) < 5e-6
        assert sm.mse(V, Y) < 1e-8 

# 需要導入模塊: import cupy [as 別名]
# 或者: from cupy import dot [as 別名]
def read_model(mapping_model_dir):
    """
        Reads the model and returns a dictionary with model parameters

    """    

    model_params={}

    for f in os.listdir(mapping_model_dir):
        if f.find('U')==0 or f.find('B')==0:
            model_params[f.replace('.csv','')]=np.loadtxt( '{}/{}'.format(mapping_model_dir,f) )

    return model_params

# def apply_mapping(x,vocab_type,model_params, latent_space=True): 
#     """
#      Applies bilingual mapping to the matrix x and returns the transformed matrix. 
     
#      vocab_type is one of `src` or `tgt`. Indicates the source or target language as per the trained model. 

#      latent_space: If true, the embeddings are mapped to latent space. Otherwise, 
#         they are mapped to the embedding space of the other language. 
#     """
   
#     xw=None 

#     if vocab_type=='src':
#         if latent_space:
#             xw = x.dot( model_params['U_src'] ).dot(scipy.linalg.sqrtm( model_params['B']  ))
#         else:
#             xw = x.dot( model_params['U_src'] ).dot( model_params['B'] ).dot( model_params['U_tgt'].T )
#     elif vocab_type=='tgt':
#         if latent_space:
#             xw = x.dot( model_params['U_tgt'] ).dot(scipy.linalg.sqrtm( model_params['B']  ))
#         else:
#             xw = x.dot( model_params['U_tgt'] ).dot( model_params['B'] ).dot( model_params['U_src'].T )

#     return xw 

# 需要導入模塊: import cupy [as 別名]
# 或者: from cupy import dot [as 別名]
def main():
    parser = argparse.ArgumentParser(
        description='SGEMM kernel call from CuPy')
    parser.add_argument('--gpu', '-g', default=0, type=int,
                        help='ID of GPU.')
    parser.add_argument(
        '--m', type=int, default=np.random.randint(1000, 1500))
    parser.add_argument(
        '--n', type=int, default=np.random.randint(1000, 1500))
    parser.add_argument(
        '--k', type=int, default=np.random.randint(500, 3000))
    args = parser.parse_args()

    print('m={} n={} k={}'.format(args.m, args.n, args.k))
    print('start benchmarking')
    print('')

    with cp.cuda.Device(args.gpu):
        A = cp.random.uniform(
            low=-1., high=1., size=(args.m, args.k)).astype(cp.float32)
        B = cp.random.uniform(
            low=-1., high=1., size=(args.k, args.n)).astype(cp.float32)

        # check correctness
        cp.testing.assert_array_almost_equal(
            sgemm(A, B), cp.dot(A, B), decimal=3)

        # dry run
        for _ in range(3):
            sgemm(A, B)
        kernel_times = benchmark(sgemm, (A, B), n_run=5)

        for _ in range(3):
            cp.dot(A, B)
        cublas_times = benchmark(cp.dot, (A, B), n_run=5)

    print('=============================Result===============================')
    print('hand written kernel time {} ms'.format(np.mean(kernel_times)))
    print('cuBLAS              time {} ms'.format(np.mean(cublas_times))) 

# 需要導入模塊: import cupy [as 別名]
# 或者: from cupy import dot [as 別名]
def pinv(a, rcond=1e-15):
    """Compute the Moore-Penrose pseudoinverse of a matrix.

    It computes a pseudoinverse of a matrix ``a``, which is a generalization
    of the inverse matrix with Singular Value Decomposition (SVD).
    Note that it automatically removes small singular values for stability.

    Args:
        a (cupy.ndarray): The matrix with dimension ``(M, N)``
        rcond (float): Cutoff parameter for small singular values.
            For stability it computes the largest singular value denoted by
            ``s``, and sets all singular values smaller than ``s`` to zero.

    Returns:
        cupy.ndarray: The pseudoinverse of ``a`` with dimension ``(N, M)``.

    .. warning::
        This function calls one or more cuSOLVER routine(s) which may yield
        invalid results if input conditions are not met.
        To detect these invalid results, you can set the `linalg`
        configuration to a value that is not `ignore` in
        :func:`cupyx.errstate` or :func:`cupyx.seterr`.

    .. seealso:: :func:`numpy.linalg.pinv`
    """
    u, s, vt = decomposition.svd(a.conj(), full_matrices=False)
    cutoff = rcond * s.max()
    s1 = 1 / s
    s1[s <= cutoff] = 0
    return core.dot(vt.T, s1[:, None] * u.T) 

# 需要導入模塊: import cupy [as 別名]
# 或者: from cupy import dot [as 別名]
def _rbf_kernel(x, y, gamma=None):
    xn, nx = x.shape
    _, ny = y.shape
    assert nx == ny, ('The number ({}) of columns of x must be the same as '
                      'the number ({}) of rows of y'.format(nx, ny))

    if gamma is None:
        gamma = 1.0 / xn

    xy = cupy.dot(x, y.transpose())
    x2 = (x * x).sum(axis=1)
    y2 = (y * y).sum(axis=1)

    return cupy.exp((x2[:, cupy.newaxis] - 2 * xy + y2) * -gamma)