Python bsddb.btopen方法代碼示例

# 需要導入模塊: import bsddb [as 別名]
# 或者: from bsddb import btopen [as 別名]
def __init__(self, resource_prefix):
        """
        Init the knowledge resource
        :param resource_prefix - the resource directory and file prefix
        """
        self.term_to_id = bsddb.btopen(resource_prefix + '_term_to_id.db', 'r')
        self.id_to_term = bsddb.btopen(resource_prefix + '_id_to_term.db', 'r')
        self.path_to_id = bsddb.btopen(resource_prefix + '_path_to_id.db', 'r')
        self.id_to_path = bsddb.btopen(resource_prefix + '_id_to_path.db', 'r')
        self.l2r_edges = bsddb.btopen(resource_prefix + '_l2r.db', 'r') 

# 需要導入模塊: import bsddb [as 別名]
# 或者: from bsddb import btopen [as 別名]
def main():
    """
    Creates a "knowledge resource" from triplets file
    """

    # Get the arguments
    args = docopt("""Creates a knowledge resource from triplets file. Second step, uses the resource files
    already created and converts the textual triplet file to a triplet file with IDs.

    Usage:
        create_resource_from_corpus_2.py <triplet_file> <resource_prefix>

        <triplet_file> = a file containing the text triplets, formated as X\tY\tpath.
        You can run this script on multiple portions of the triplet file at once and concatenate the output.
        <resource_prefix> = the file names' prefix for the resource files
    """)

    triplet_file = args['<triplet_file>']
    resource_prefix = args['<resource_prefix>']

    # Load the resource DBs
    term_to_id_db = bsddb.btopen(resource_prefix + '_term_to_id.db')
    path_to_id_db = bsddb.btopen(resource_prefix + '_path_to_id.db')

    with codecs.open(triplet_file) as f_in:
        with codecs.open(triplet_file + '_id', 'w') as f_out:
            for line in f_in:
                try:
                    x, y, path = line.strip().split('\t')
                except:
                    print line
                    continue

                # Frequent path
                x_id, y_id, path_id = term_to_id_db[x], term_to_id_db[y], path_to_id_db.get(path, -1)
                if path_id != -1:
                    print >> f_out, '\t'.join(map(str, (x_id, y_id, path_id))) 

# 需要導入模塊: import bsddb [as 別名]
# 或者: from bsddb import btopen [as 別名]
def test_keyordering(self):
        if self.openmethod[0] is not bsddb.btopen:
            return
        keys = self.d.keys()
        keys.sort()
        self.assertEqual(self.f.first()[0], keys[0])
        self.assertEqual(self.f.next()[0], keys[1])
        self.assertEqual(self.f.last()[0], keys[-1])
        self.assertEqual(self.f.previous()[0], keys[-2])
        self.assertEqual(list(self.f), keys) 

# 需要導入模塊: import bsddb [as 別名]
# 或者: from bsddb import btopen [as 別名]
def db_dump(filename, outfile = sys.stdout):
  try:
    f = bsddb.hashopen(filename, 'r')
    db_type = "hash"
  except:
    f = bsddb.btopen(filename, 'r')
    db_type = "btree"

  outfile.write("VERSION=3\n") # magic
  outfile.write("format=bytevalue\n")
  outfile.write("type=%s\n" % (db_type))

  outfile.write("HEADER=END\n")
  for (key,value) in f.iteritems():
    outfile.write(" ")
    for c in key:
      outfile.write("%02x" % ord(c))
    outfile.write("\n")

    outfile.write(" ")
    for c in value:
      outfile.write("%02x" % ord(c))
    outfile.write("\n")
  outfile.write("DATA=END\n")

#-----------------------------------------------------------------------------
# vim:ft=python 

# 需要導入模塊: import bsddb [as 別名]
# 或者: from bsddb import btopen [as 別名]
def main():
    """
    Creates a "knowledge resource" from triplets file
    """

    # Get the arguments
    args = docopt("""Creates a knowledge resource from triplets file. Third step, uses the ID-based triplet file
    and converts it to the '_l2r.db' file.

    Usage:
        create_resource_from_corpus_3.py <id_triplet_file> <resource_prefix>

        <id_triplet_file> = a file containing the int triplets, formated as X_id\tY_id\tpath_id\tcount, where
        count is the number of times X and Y occurred together in this path. You can obtain such a file by
        counting the number of occurrences of each line in the file produced by the second step, e.g.:
        awk '{i[$0]++} END{for(x in i){print x"\t"i[x]}}' triplet_file > id_triplet_file

        If you split the files in the second step, apply this command to each one of them, and then sum them up, e.g.:
        for each i, run: awk '{i[$0]++} END{for(x in i){print x"\t"i[x]}}' triplet_file_i > id_triplet_file_i
        cat id_triplet_file_* > id_triplet_file_temp

        Then, run: awk -F$'\t' '{i[$1,"\t",$2,"\t",$3]+=$4} END{for(x in i){print x"\t"i[x]}}' id_triplet_file_temp > id_triplet_file

        <resource_prefix> = the file names' prefix for the resource files
    """)

    id_triplet_file = args['<id_triplet_file>']
    resource_prefix = args['<resource_prefix>']

    l2r_db = bsddb.btopen(resource_prefix + '_l2r.db', 'c')
    l2r_dict = defaultdict(str)

    with codecs.open(id_triplet_file) as f_in:
        for ct, line in tqdm(enumerate(f_in)):
            try:
                x, y, path, count = line.strip().split('\t')
            except:
                print line
                continue

            key = '%s###%s' % (x, y)
            current = '%s:%s' % (path, count)
            # previous = l2r_db.get(key, '')
            l2r_dict[key] += current + ','

            # if previous != '':
            #     previous += ','

            # l2r_db[key] = previous + current
            # if ct % 1000000 == 0:
            #     l2r_db.sync()
    for k, v in l2r_dict.items():
        l2r_db[k] = v.rstrip(',')

    l2r_db.sync() 

# 需要導入模塊: import bsddb [as 別名]
# 或者: from bsddb import btopen [as 別名]
def __init_dbd__(self):
        print "prepare to initial the bdb"
        print "[#] Check if the db exist"
        if os.path.exists("all_sites.db"):
            os.remove('all_sites.db')

        if os.path.exists('visited.db'):
            os.remove('visited.db')
        print "[#] Cleared the db"
            
        """
>>> import bsddb
>>> db = bsddb.btopen('spam.db', 'c')
>>> for i in range(10): db['%d'%i] = '%d'% (i*i)
...
>>> db['3']
'9'
>>> db.keys()
['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
>>> db.first()
('0', '0')
>>> db.next()
('1', '1')
>>> db.last()
('9', '81')
>>> db.set_location('2')
('2', '4')
>>> db.previous()
('1', '1')
>>> for k, v in db.iteritems():
...     print k, v
0 0
1 1
2 4
3 9
4 16
5 25
6 36
7 49
8 64
9 81
>>> '8' in db
True
>>> db.sync()
0

        """
        try:
            self.all_sites  = bsddb.btopen(file = 'all_sites.db',   flag = 'c')
            self.visited    = bsddb.btopen(file = 'visited.db',     flag = 'c') 
            print "[*]Success init BDB"
        except:
            print "[!]Bad ! Can't create BDB!"