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Python Request.meta['category']方法代碼示例

本文整理匯總了Python中scrapy.http.request.Request.meta['category']方法的典型用法代碼示例。如果您正苦於以下問題:Python Request.meta['category']方法的具體用法?Python Request.meta['category']怎麽用?Python Request.meta['category']使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在scrapy.http.request.Request的用法示例。


在下文中一共展示了Request.meta['category']方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: parse

# 需要導入模塊: from scrapy.http.request import Request [as 別名]
# 或者: from scrapy.http.request.Request import meta['category'] [as 別名]
    def parse(self, response):
        ''' Parse response from start urls (/channels)
            
            Channels are groups by category. So, this spider extracts the 
            category of each channel, and constructs a request with the meta 
            information of the category (that information would not be 
            available from the channel page otherwise)
        '''
        self.logger.debug("Parse url {}".format(response.url))        

        cat_container = response.xpath('/html/body/div[1]/div/article/div')
        
        # Channels are grouped by category in containers with class '.channel-category'
        for cat in cat_container.css('.channel-category'):
            # extract the title of the category
            cat_title = cat.xpath('h2/text()').extract_first()            
            # extract the link to the channel pages
            for channel in cat.css('ul.channel-grid li'):
                link = channel.xpath('a//@href').extract_first()
                full_link = loaders.contextualize(link, base_url=response.url)
                # Construct request               
                request = Request(full_link, callback=self.parse_channel)
                request.meta['category'] = cat_title
                
                yield request
開發者ID:miguelcb84,項目名稱:ewe-scrapers,代碼行數:27,代碼來源:ifttt_spiders.py


注:本文中的scrapy.http.request.Request.meta['category']方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。