本文整理匯總了Python中rogerthat.models.UserProfile.list_by_service_role_email方法的典型用法代碼示例。如果您正苦於以下問題：Python UserProfile.list_by_service_role_email方法的具體用法？Python UserProfile.list_by_service_role_email怎麽用？Python UserProfile.list_by_service_role_email使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類rogerthat.models.UserProfile的用法示例。
在下文中一共展示了UserProfile.list_by_service_role_email方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: get_service_grants
# 需要導入模塊: from rogerthat.models import UserProfile [as 別名]
# 或者: from rogerthat.models.UserProfile import list_by_service_role_email [as 別名]
def get_service_grants(service_user, filtered_service_identity=ServiceIdentity.DEFAULT, filtered_role_id=None,
filtered_role_type=None):
from rogerthat.bizz.roles import ROLE_TYPE_ADMIN, ROLE_TYPE_SERVICE
service_user_email = service_user.email()
if not isinstance(service_user_email, unicode):
service_user_email = service_user_email.decode('utf-8')
profiles = UserProfile.list_by_service_role_email(service_user_email)
for p in profiles:
for si, roles in p.grants.iteritems():
if si.startswith(service_user_email + '/'):
_, identity = get_service_identity_tuple(users.User(si))
if filtered_service_identity != ServiceIdentity.DEFAULT and identity != filtered_service_identity:
continue
for role in roles:
gto = GrantTO()
try:
role_id = int(role)
role_type = ROLE_TYPE_SERVICE
role = None
except ValueError: # build-int role (see ROLES constant)
role_id = -1
role_type = ROLE_TYPE_ADMIN
gto.role_type = role_type
gto.role_id = role_id
gto.role = role
if filtered_role_id is not None and filtered_role_id != gto.role_id:
continue
if filtered_role_type is not None and filtered_role_type != gto.role_type:
continue
gto.identity = identity
gto.service_email = service_user_email
gto.user_email = get_human_user_from_app_user(p.user).email()
gto.user_name = p.name
gto.user_avatar_id = p.avatarId
gto.app_id = p.app_id
yield gto