本文整理匯總了Python中pypy.annotation.model.SomeObject.const方法的典型用法代碼示例。如果您正苦於以下問題：Python SomeObject.const方法的具體用法？Python SomeObject.const怎麽用？Python SomeObject.const使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類pypy.annotation.model.SomeObject的用法示例。
在下文中一共展示了SomeObject.const方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: union
# 需要導入模塊: from pypy.annotation.model import SomeObject [as 別名]
# 或者: from pypy.annotation.model.SomeObject import const [as 別名]
def union((obj1, obj2)):
if obj1 == obj2:
return obj1
else:
result = SomeObject()
if obj1.knowntype == obj2.knowntype and obj1.knowntype != object:
result.knowntype = obj1.knowntype
is_type_of1 = getattr(obj1, 'is_type_of', None)
is_type_of2 = getattr(obj2, 'is_type_of', None)
if obj1.is_immutable_constant() and obj2.is_immutable_constant() and obj1.const == obj2.const:
result.const = obj1.const
is_type_of = {}
if is_type_of1:
for v in is_type_of1:
is_type_of[v] = True
if is_type_of2:
for v in is_type_of2:
is_type_of[v] = True
if is_type_of:
result.is_type_of = is_type_of.keys()
else:
if is_type_of1 and is_type_of1 == is_type_of2:
result.is_type_of = is_type_of1
# try to preserve the origin of SomeObjects
if obj1 == result:
result = obj1
elif obj2 == result:
result = obj2
unioncheck(result)
return result