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Python Product.get_published_products方法代碼示例

本文整理匯總了Python中products.models.Product.get_published_products方法的典型用法代碼示例。如果您正苦於以下問題:Python Product.get_published_products方法的具體用法?Python Product.get_published_products怎麽用?Python Product.get_published_products使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在products.models.Product的用法示例。


在下文中一共展示了Product.get_published_products方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: rubricator

# 需要導入模塊: from products.models import Product [as 別名]
# 或者: from products.models.Product import get_published_products [as 別名]
def rubricator(request):
    rubric_id = request.GET.get("rubric", None)
    rubric = None
    rubrics = Rubric.get_published_rubrics().filter(parent=None)
    if rubric_id is not None :
        try:
            rubric = Rubric.objects.get(id=rubric_id)
        except Rubric.DoesNotExist :
            return error(request, u"Нет рубрики с таким идентификатором!", u"")
    rubricator_path = []
    parents_id = []
    rubrics_view = rubrics
    products = Product.get_published_products()
    products_count = products.count()
    if rubric is not None :
        rubricator_path = rubric.rubricator_path()
        parents_id = map(lambda r: r.id, rubricator_path)
        all_children = rubric.get_all_published_children()
        products = products.filter(Q(rubrics__in=all_children)|Q(rubrics__in=[rubric]))
        rubrics_view = all_children
        if len(rubrics_view) :
            products = products.order_by("?")[:21]
        else:
            products_count = products.count()
            paginator = Paginator(products, 21)
             
            page = request.GET.get('page')
            try:
                products = paginator.page(page)
            except PageNotAnInteger:
                products = paginator.page(1)
            except EmptyPage:
                products = paginator.page(paginator.num_pages)
    else:
        products = products.order_by("?")[:21]
    return render_to_response("rubrics/rubrics.html", {'main': rubric, 'products':products, 'products_count':products_count, 'rubrics_view':rubrics_view, 'rubrics':rubrics, 'parents_id':parents_id, 'rubricator_path':rubricator_path}, get_context(request))
開發者ID:durm,項目名稱:aksvrnru,代碼行數:38,代碼來源:views.py


注:本文中的products.models.Product.get_published_products方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。