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Python PackageId.validate_name方法代碼示例

本文整理匯總了Python中pkgpanda.PackageId.validate_name方法的典型用法代碼示例。如果您正苦於以下問題:Python PackageId.validate_name方法的具體用法?Python PackageId.validate_name怎麽用?Python PackageId.validate_name使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在pkgpanda.PackageId的用法示例。


在下文中一共展示了PackageId.validate_name方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: _get_package_list

# 需要導入模塊: from pkgpanda import PackageId [as 別名]
# 或者: from pkgpanda.PackageId import validate_name [as 別名]
    def _get_package_list(treeinfo_dict, key, excludes=None):
        """Return a list of package name strings from treeinfo_dict by key.

        If key isn't present in treeinfo_dict, an empty list is returned.

        """
        excludes = excludes or list()
        package_list = treeinfo_dict.get(key, list())

        # Validate package list.
        if not isinstance(package_list, list):
            raise BuildError("{} must be either null (meaning don't use) or a list of package names.".format(key))
        for package_name in package_list:
            if not isinstance(package_name, str):
                raise BuildError("{} must be a list of strings. Found a {} with the value: {}".format(
                    key, type(package_name), package_name))

            try:
                PackageId.validate_name(package_name)
            except ValidationError as ex:
                raise BuildError("Invalid package name in {}: {}".format(key, package_name)) from ex

            if package_name in excludes:
                raise BuildError("Package found in both exclude and {}: {}".format(key, package_name))

        return package_list
開發者ID:alberts,項目名稱:dcos,代碼行數:28,代碼來源:__init__.py


注:本文中的pkgpanda.PackageId.validate_name方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。