本文整理匯總了Python中ometa.runtime.OMetaBase.rule_exactly方法的典型用法代碼示例。如果您正苦於以下問題：Python OMetaBase.rule_exactly方法的具體用法？Python OMetaBase.rule_exactly怎麽用？Python OMetaBase.rule_exactly使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類ometa.runtime.OMetaBase的用法示例。
在下文中一共展示了OMetaBase.rule_exactly方法的4個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: test_exactlyFail
# 需要導入模塊: from ometa.runtime import OMetaBase [as 別名]
# 或者: from ometa.runtime.OMetaBase import rule_exactly [as 別名]
def test_exactlyFail(self):
"""
L{OMetaBase.rule_exactly} raises L{ParseError} when the requested item
doesn't match the input. The error contains info on what was expected
and the position.
"""
data = "foo"
o = OMetaBase(data)
with self.assertRaises(ParseError) as e:
o.rule_exactly("g")
self.assertEquals(e.exception[1], expected(None, "g"))
self.assertEquals(e.exception[0], 0)示例2: test_many
# 需要導入模塊: from ometa.runtime import OMetaBase [as 別名]
# 或者: from ometa.runtime.OMetaBase import rule_exactly [as 別名]
def test_many(self):
"""
L{OMetaBase.many} returns a list of parsed values and the error that
caused the end of the loop.
"""
data = "ooops"
o = OMetaBase(data)
self.assertEqual(o.many(lambda: o.rule_exactly("o")), (["o"] * 3, ParseError(o.input, 3, expected(None, "o"))))示例3: test_exactly_multi
# 需要導入模塊: from ometa.runtime import OMetaBase [as 別名]
# 或者: from ometa.runtime.OMetaBase import rule_exactly [as 別名]
def test_exactly_multi(self):
"""
L{OMetaBase.rule_exactly} returns the requested item from the input
string along with its position, if it's there.
"""
data = "foo"
o = OMetaBase(data)
v, e = o.rule_exactly("fo")
self.assertEqual(v, "fo")
self.assertEqual(e[0], 0)示例4: test_label
# 需要導入模塊: from ometa.runtime import OMetaBase [as 別名]
# 或者: from ometa.runtime.OMetaBase import rule_exactly [as 別名]
def test_label(self):
"""
L{OMetaBase.label} returns a list of parsed values and the error that
caused the end of the loop.
"""
data = "ooops"
label = 'CustomLabel'
o = OMetaBase(data)
exc = self.assertRaises(
ParseError, o.label, lambda: o.rule_exactly('x'), label)
self.assertEqual(exc,
ParseError(o.input, 0, expected(label)).withMessage([("Custom Exception:", label, None)]))