本文整理匯總了Python中odemis.model.CancellableThreadPoolExecutor.get_next_future方法的典型用法代碼示例。如果您正苦於以下問題：Python CancellableThreadPoolExecutor.get_next_future方法的具體用法？Python CancellableThreadPoolExecutor.get_next_future怎麽用？Python CancellableThreadPoolExecutor.get_next_future使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類odemis.model.CancellableThreadPoolExecutor的用法示例。
在下文中一共展示了CancellableThreadPoolExecutor.get_next_future方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: AntiBacklashActuator
# 需要導入模塊: from odemis.model import CancellableThreadPoolExecutor [as 別名]
# 或者: from odemis.model.CancellableThreadPoolExecutor import get_next_future [as 別名]
#.........這裏部分代碼省略.........
sub_shift[a] = v
else:
# optimisation: if move goes in the same direction as backlash
# correction, then no need to do the correction
# TODO: only do this if backlash correction has already been applied once?
if v * self._backlash[a] >= 0:
sub_shift[a] = v
else:
with self._shifted_lock:
if self._shifted[a]:
sub_shift[a] = v
else:
sub_shift[a] = v - self._backlash[a]
self._shifted[a] = True
# Do the backlash + move
axes = set(shift.keys())
if not any(self._shifted):
# a tiny bit faster as we don't sleep
self._child.moveRelSync(sub_shift)
else:
# some antibacklash move needed afterwards => update might be worthy
f = self._child.moveRel(sub_shift)
done = False
while not done:
try:
f.result(timeout=0.01)
except futures.TimeoutError:
pass # Keep waiting for end of move
else:
done = True
# Check if there is already a new move to do
nf = self._executor.get_next_future(future)
if nf is not None and axes <= nf._update_axes:
logging.debug("Ending move control early as next move is an update containing %s", axes)
return
# backlash move
self._antiBacklashMove(shift.keys())
def _doMoveAbs(self, future, pos):
sub_pos = {}
for a, v in pos.items():
if a not in self._backlash:
sub_pos[a] = v
else:
shift = v - self.position.value[a]
with self._shifted_lock:
if shift * self._backlash[a] >= 0:
sub_pos[a] = v
self._shifted[a] = False
else:
sub_pos[a] = v - self._backlash[a]
self._shifted[a] = True
# Do the backlash + move
axes = set(pos.keys())
if not any(self._shifted):
# a tiny bit faster as we don't sleep
self._child.moveAbsSync(sub_pos)
else: # some antibacklash move needed afterwards => update might be worthy
f = self._child.moveAbs(sub_pos)
done = False
while not done:
try: