本文整理匯總了Python中models.Issue.client方法的典型用法代碼示例。如果您正苦於以下問題：Python Issue.client方法的具體用法？Python Issue.client怎麽用？Python Issue.client使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類models.Issue的用法示例。
在下文中一共展示了Issue.client方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: test_m2m_and_m2o
# 需要導入模塊: from models import Issue [as 別名]
# 或者: from models.Issue import client [as 別名]
def test_m2m_and_m2o(self):
r = User.objects.create(username="russell")
g = User.objects.create(username="gustav")
i1 = Issue(num=1)
i1.client = r
i1.save()
i2 = Issue(num=2)
i2.client = r
i2.save()
i2.cc.add(r)
i3 = Issue(num=3)
i3.client = g
i3.save()
i3.cc.add(r)
self.assertQuerysetEqual(
Issue.objects.filter(client=r.id), [
1,
2,
],
lambda i: i.num
)
self.assertQuerysetEqual(
Issue.objects.filter(client=g.id), [
3,
],
lambda i: i.num
)
self.assertQuerysetEqual(
Issue.objects.filter(cc__id__exact=g.id), []
)
self.assertQuerysetEqual(
Issue.objects.filter(cc__id__exact=r.id), [
2,
3,
],
lambda i: i.num
)
# These queries combine results from the m2m and the m2o relationships.
# They're three ways of saying the same thing.
self.assertQuerysetEqual(
Issue.objects.filter(Q(cc__id__exact = r.id) | Q(client=r.id)), [
1,
2,
3,
],
lambda i: i.num
)
self.assertQuerysetEqual(
Issue.objects.filter(cc__id__exact=r.id) | Issue.objects.filter(client=r.id), [
1,
2,
3,
],
lambda i: i.num
)
self.assertQuerysetEqual(
Issue.objects.filter(Q(client=r.id) | Q(cc__id__exact=r.id)), [
1,
2,
3,
],
lambda i: i.num
)