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Python Folder.get_relative_path方法代碼示例

本文整理匯總了Python中fswrap.Folder.get_relative_path方法的典型用法代碼示例。如果您正苦於以下問題:Python Folder.get_relative_path方法的具體用法?Python Folder.get_relative_path怎麽用?Python Folder.get_relative_path使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在fswrap.Folder的用法示例。


在下文中一共展示了Folder.get_relative_path方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: Node

# 需要導入模塊: from fswrap import Folder [as 別名]
# 或者: from fswrap.Folder import get_relative_path [as 別名]

#.........這裏部分代碼省略.........
    """
    Represents any folder that is processed by hyde
    """

    def __init__(self, source_folder, parent=None):
        super(Node, self).__init__(source_folder)
        if not source_folder:
            raise HydeException("Source folder is required"
                                " to instantiate a node.")
        self.root = self
        self.module = None
        self.site = None
        self.source_folder = Folder(str(source_folder))
        self.parent = parent
        if parent:
            self.root = self.parent.root
            self.module = self.parent.module if self.parent.module else self
            self.site = parent.site
        self.child_nodes = []
        self.resources = []

    def contains_resource(self, resource_name):
        """
        Returns True if the given resource name exists as a file
        in this node's source folder.
        """

        return File(self.source_folder.child(resource_name)).exists

    def get_resource(self, resource_name):
        """
        Gets the resource if the given resource name exists as a file
        in this node's source folder.
        """

        if self.contains_resource(resource_name):
            return self.root.resource_from_path(
                self.source_folder.child(resource_name))
        return None

    def add_child_node(self, folder):
        """
        Creates a new child node and adds it to the list of child nodes.
        """

        if folder.parent != self.source_folder:
            raise HydeException("The given folder [%s] is not a"
                                " direct descendant of [%s]" %
                                (folder, self.source_folder))
        node = Node(folder, self)
        self.child_nodes.append(node)
        return node

    def add_child_resource(self, afile):
        """
        Creates a new resource and adds it to the list of child resources.
        """

        if afile.parent != self.source_folder:
            raise HydeException("The given file [%s] is not"
                                " a direct descendant of [%s]" %
                                (afile, self.source_folder))
        resource = Resource(afile, self)
        self.resources.append(resource)
        return resource

    def walk(self):
        """
        Walks the node, first yielding itself then
        yielding the child nodes depth-first.
        """
        yield self
        for child in sorted([node for node in self.child_nodes]):
            for node in child.walk():
                yield node

    def rwalk(self):
        """
        Walk the node upward, first yielding itself then
        yielding its parents.
        """
        x = self
        while x:
            yield x
            x = x.parent

    def walk_resources(self):
        """
        Walks the resources in this hierarchy.
        """
        for node in self.walk():
            for resource in sorted([resource for resource in node.resources]):
                yield resource

    @property
    def relative_path(self):
        """
        Gets the path relative to the root folder (Content, Media, Layout)
        """
        return self.source_folder.get_relative_path(self.root.source_folder)
開發者ID:LestherSK,項目名稱:hyde,代碼行數:104,代碼來源:site.py


注:本文中的fswrap.Folder.get_relative_path方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。