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Python FlaskAPI.config['UPLOAD_FOLDER']方法代碼示例

本文整理匯總了Python中flask.ext.api.FlaskAPI.config['UPLOAD_FOLDER']方法的典型用法代碼示例。如果您正苦於以下問題:Python FlaskAPI.config['UPLOAD_FOLDER']方法的具體用法?Python FlaskAPI.config['UPLOAD_FOLDER']怎麽用?Python FlaskAPI.config['UPLOAD_FOLDER']使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在flask.ext.api.FlaskAPI的用法示例。


在下文中一共展示了FlaskAPI.config['UPLOAD_FOLDER']方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: FlaskAPI

# 需要導入模塊: from flask.ext.api import FlaskAPI [as 別名]
# 或者: from flask.ext.api.FlaskAPI import config['UPLOAD_FOLDER'] [as 別名]
from flask.ext.api import FlaskAPI
import os
from flask import request
from werkzeug import secure_filename
import subprocess
import json
import requests

app = FlaskAPI(__name__)
UPLOAD_FOLDER = '/home/miguel/'
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER


@app.route('/send-image', methods=['POST', 'GET'])
def process_image():
    print "Processing image!"
    if request.method == 'POST':
        file = request.files['file']
        if file:
            filename = secure_filename(file.filename)
            file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
            print "imagen guardada con nombre {}".format(filename)
            # imagen = open(filename, 'rb')
            command = "alpr /home/miguel/{} -n 1 -j".format(filename)
            process = subprocess.Popen(command.split(), stdout=subprocess.PIPE)
            print "comando ejecutado"
            output = json.loads(process.communicate()[0])
            print "Despues del output"
            true_plate = output['results'][0]['plate']
            print true_plate
            response = requests.get('http://greenheadapi.azurewebsites.net/api/place/getzone/{}'.format(true_plate))
開發者ID:IoTEquipo13,項目名稱:Edison,代碼行數:33,代碼來源:app.py


注:本文中的flask.ext.api.FlaskAPI.config['UPLOAD_FOLDER']方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。