本文整理匯總了Python中etk.docking.DockGroup.get_current_item方法的典型用法代碼示例。如果您正苦於以下問題：Python DockGroup.get_current_item方法的具體用法？Python DockGroup.get_current_item怎麽用？Python DockGroup.get_current_item使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類etk.docking.DockGroup的用法示例。
在下文中一共展示了DockGroup.get_current_item方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: test_get_current_item
# 需要導入模塊: from etk.docking import DockGroup [as 別名]
# 或者: from etk.docking.DockGroup import get_current_item [as 別名]
def test_get_current_item(self):
dockitem = DockItem()
dockgroup = DockGroup()
self.assertTrue(dockgroup.get_current_item() is None)
index = dockgroup.append_item(dockitem)
self.assertTrue(dockgroup.get_current_item() == index)
dockgroup.remove(dockitem)
self.assertTrue(dockgroup.get_current_item() is None)
dockitem.destroy()
dockgroup.destroy()示例2: test_prev_item
# 需要導入模塊: from etk.docking import DockGroup [as 別名]
# 或者: from etk.docking.DockGroup import get_current_item [as 別名]
def test_prev_item(self):
dockitem1 = DockItem()
dockitem2 = DockItem()
dockgroup = DockGroup()
dockgroup.add(dockitem1)
dockgroup.add(dockitem2)
self.assertTrue(dockgroup.get_current_item() == 1)
dockgroup.prev_item()
self.assertTrue(dockgroup.get_current_item() == 0)
dockgroup.prev_item()
self.assertTrue(dockgroup.get_current_item() == 0)
dockitem1.destroy()
dockitem2.destroy()
dockgroup.destroy()示例3: test_set_current_item
# 需要導入模塊: from etk.docking import DockGroup [as 別名]
# 或者: from etk.docking.DockGroup import get_current_item [as 別名]
def test_set_current_item(self):
dockitem1 = DockItem()
dockitem2 = DockItem()
dockgroup = DockGroup()
self.assertTrue(dockgroup.get_current_item() is None)
index = dockgroup.append_item(dockitem1)
self.assertTrue(dockgroup.get_current_item() == index)
index = dockgroup.append_item(dockitem2)
self.assertTrue(dockgroup.get_current_item() == index)
dockgroup.set_current_item(0)
self.assertTrue(dockgroup.get_current_item() == 0)
dockgroup.set_current_item(len(dockgroup) + 10)
self.assertTrue(dockgroup.get_current_item() == len(dockgroup) - 1)
dockgroup.set_current_item(-1)
self.assertTrue(dockgroup.get_current_item() == 0)
dockitem1.destroy()
dockitem2.destroy()
dockgroup.destroy()