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Python Course.get_all_by_crn方法代碼示例

本文整理匯總了Python中course.Course.get_all_by_crn方法的典型用法代碼示例。如果您正苦於以下問題:Python Course.get_all_by_crn方法的具體用法?Python Course.get_all_by_crn怎麽用?Python Course.get_all_by_crn使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在course.Course的用法示例。


在下文中一共展示了Course.get_all_by_crn方法的3個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Python代碼示例。

示例1: __make_schedule

# 需要導入模塊: from course import Course [as 別名]
# 或者: from course.Course import get_all_by_crn [as 別名]
	def __make_schedule(requirements, current_schedule):
		if len(requirements) == 0:
			return current_schedule

		requirement = requirements[0]
		requirements = requirements[1:]

		for course in requirement.valid_courses:
			if len(Course.get_all_by_crn(course)) == 0:
				raise Exception("No class in catalog; %s" % course)
			for c in Course.get_all_by_crn(course):
				# Check to see if this course conflicts with anything
				conflicts = False
				for c2 in current_schedule:
					if c.timeslot.conflicts(c2.timeslot):
						conflicts = True
						break

				if not conflicts:
					# Make sure we can take it, then recurse
					schedule = []
					if not c.can_take(current_schedule, credit_hour_limit=max_credits):
						schedule =  __make_schedule(requirements, current_schedule)
						if schedule == False:
							continue
						# If we still can't take it, continue
						if not c.can_take(schedule, credit_hour_limit=max_credits):
							continue
						schedule += [c]
					else:
						schedule = __make_schedule(requirements, current_schedule + [c])
					if schedule != False:
						return schedule
		return False
開發者ID:chuck211991,項目名稱:teamblue_xinformatics,代碼行數:36,代碼來源:schedule.py

示例2: test_get_courses_by_crn

# 需要導入模塊: from course import Course [as 別名]
# 或者: from course.Course import get_all_by_crn [as 別名]
	def test_get_courses_by_crn(self):
		# Timeslot can be empty for this
		c1 = Course("CSCI2121", None)
		c2 = Course("CSCI2121", None)
		c3 = Course("CSCI2121", None)
		c4 = Course("CSCI2122", None)
		
		self.assertEquals(3, len(Course.get_all_by_crn("CSCI2121")))
開發者ID:chuck211991,項目名稱:teamblue_xinformatics,代碼行數:10,代碼來源:test_course.py

示例3: get_worst_crn

# 需要導入模塊: from course import Course [as 別名]
# 或者: from course.Course import get_all_by_crn [as 別名]
	def get_worst_crn(self):
		lowest = self.valid_courses[0]
		for c in self.valid_courses[1:]:
			if len(Course.get_all_by_crn(c)) < len(Course.get_all_by_crn(lowest)):
				lowest = c
		return len(Course.get_all_by_crn(lowest))
開發者ID:hayntopdawg,項目名稱:teamblue_xinformatics,代碼行數:8,代碼來源:requirement.py


注:本文中的course.Course.get_all_by_crn方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。