本文整理匯總了Python中LinkedList.LinkedList.insertAfter方法的典型用法代碼示例。如果您正苦於以下問題：Python LinkedList.insertAfter方法的具體用法？Python LinkedList.insertAfter怎麽用？Python LinkedList.insertAfter使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類LinkedList.LinkedList的用法示例。
在下文中一共展示了LinkedList.insertAfter方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: _getProximityQueryTermPostingList
# 需要導入模塊: from LinkedList import LinkedList [as 別名]
# 或者: from LinkedList.LinkedList import insertAfter [as 別名]
def _getProximityQueryTermPostingList(self, term1String, term2String, distance):
term1 = self._getQueryTermPostingList(term1String);
term2 = self._getQueryTermPostingList(term2String);
docs1 = term1.docs._head;
docs2 = term2.docs._head;
newDocs1 = LinkedList();
newDocs2 = LinkedList();
termHasDocs = False
while (docs1 is not None) and (docs2 is not None):
if docs1.value == docs2.value:
if self._docHasTokensWithinDistance(docs1.value, docs2.value, distance):
newDocs1.insertAfter(docs1.value);
newDocs2.insertAfter(docs2.value);
termHasDocs = True;
docs1 = docs1.next;
docs2 = docs2.next;
else:
if docs1.value < docs2.value: docs1 = docs1.next;
else: docs2 = docs2.next;
# transfer term count per document to truncated list
newDocs1.count = term1.count
newDocs2.count = term2.count
# exchange full document term count with truncated list
term1.docs = newDocs1;
term2.docs = newDocs2;
if termHasDocs: return term1, term2;
else: return None, None示例2: comment
# 需要導入模塊: from LinkedList import LinkedList [as 別名]
# 或者: from LinkedList.LinkedList import insertAfter [as 別名]
comment("FAIL -> " + test_name +"\nsize debe ser 0 cuando la lista esta vacia")
grade(0)
except:
e = sys.exc_info()[1]
comment("FAIL -> " + test_name + "\n" + str(e))
grade(0)
# Check one element list - insertAfter
try:
test_name = 'LinkedList con un elemento: insertAfter()'
l = LinkedList()
l.insertAfter(17)
if l.head != l.tail or l.head != l.current:
comment("FAIL -> " + test_name+"\n head, tail y current deben apuntar al mismo nodo cuando solo hay un elemento")
grade(0)
else:
if l.current.getData() != 17:
comment("FAIL -> " + test_name +"\n getData() no funciona correctamente cuando la lista tiene un solo elemento")
grade(0)
else:
if l.current.getNext() != None:
comment("FAIL -> " + test_name +"\n getNext() no funciona correctamente cuando la lista tiene un solo elemento. getNext() deberia devolver None en este caso")
grade(0)
else:
if l.size != 1:
comment("FAIL -> " + test_name +"\n La variable size no se incrementa correctamente")
grade(0)