本文整理匯總了Python中AccessControl.SecurityManagement.noSecurityManager方法的典型用法代碼示例。如果您正苦於以下問題：Python SecurityManagement.noSecurityManager方法的具體用法？Python SecurityManagement.noSecurityManager怎麽用？Python SecurityManagement.noSecurityManager使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類AccessControl.SecurityManagement的用法示例。
在下文中一共展示了SecurityManagement.noSecurityManager方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Python代碼示例。
示例1: tearDown
# 需要導入模塊: from AccessControl import SecurityManagement [as 別名]
# 或者: from AccessControl.SecurityManagement import noSecurityManager [as 別名]
def tearDown(self):
IStatusMessage(self.request).show()
if 'HTTP_REFERER' in self.request.environ:
del self.request.environ['HTTP_REFERER']
SecurityManagement.noSecurityManager()
if 'location' in self.request.response.headers:
del self.request.response.headers['location']示例2: test_add_portlet_fails_with_anonymous
# 需要導入模塊: from AccessControl import SecurityManagement [as 別名]
# 或者: from AccessControl.SecurityManagement import noSecurityManager [as 別名]
def test_add_portlet_fails_with_anonymous(self):
portal = self.layer['portal']
request = self.layer['request']
request.environ['HTTP_X_BRIDGE_ORIGIN'] = 'client-one'
request.form['path'] = '@@watcher-feed?uid=567891234'
sm = SecurityManagement.getSecurityManager()
SecurityManagement.noSecurityManager()
try:
view = queryMultiAdapter((portal, request),
name='add-watcher-portlet')
with self.assertRaises(Exception) as cm:
view()
self.assertEqual(str(cm.exception), 'Could not find userid.')
finally:
SecurityManagement.setSecurityManager(sm)示例3: tearDown
# 需要導入模塊: from AccessControl import SecurityManagement [as 別名]
# 或者: from AccessControl.SecurityManagement import noSecurityManager [as 別名]
def tearDown(self):
SecurityManagement.noSecurityManager()