本文整理匯總了PHP中Symfony\Component\Security\Core\User\UserProviderInterface::supportsClass方法的典型用法代碼示例。如果您正苦於以下問題：PHP UserProviderInterface::supportsClass方法的具體用法？PHP UserProviderInterface::supportsClass怎麽用？PHP UserProviderInterface::supportsClass使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Symfony\Component\Security\Core\User\UserProviderInterface的用法示例。
在下文中一共展示了UserProviderInterface::supportsClass方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: supportsClass
/**
* Whether this provider supports the given user class.
*
* @param string $class
*
* @return bool
*/
public function supportsClass($class)
{
if ($this->provider) {
return $this->provider->supportsClass($class);
}
return false;
}示例2: getUser
public function getUser($credentials, UserProviderInterface $userProvider)
{
/** @var AccessToken $accessToken */
$accessToken = $credentials;
try {
if ($userProvider->supportsClass($accessToken->getResourceOwner()->getResourceOwnerType())) {
$userAccount = $userProvider->loadUserByUsername($accessToken->getResourceOwner()->getResourceOwnerId());
return $userAccount;
}
} catch (UsernameNotFoundException $e) {
// nothing to do
}
return null;
}示例3: supportsClass
/**
* {@inheritDoc}
*/
public function supportsClass($class)
{
return $this->userProvider->supportsClass($class);
}