本文整理匯總了PHP中Symfony\Component\Form\FormConfigBuilder::setFormFactory方法的典型用法代碼示例。如果您正苦於以下問題：PHP FormConfigBuilder::setFormFactory方法的具體用法？PHP FormConfigBuilder::setFormFactory怎麽用？PHP FormConfigBuilder::setFormFactory使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Symfony\Component\Form\FormConfigBuilder的用法示例。
在下文中一共展示了FormConfigBuilder::setFormFactory方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: testFormErrorsWithNonFormComponents
public function testFormErrorsWithNonFormComponents()
{
if (!class_exists(SubmitType::class)) {
$this->markTestSkipped('Not using Symfony Form >= 2.3 with submit type');
}
$dispatcher = $this->createMock(EventDispatcherInterface::class);
$factoryBuilder = new FormFactoryBuilder();
$factoryBuilder->addType(new SubmitType());
$factoryBuilder->addType(new ButtonType());
$factory = $factoryBuilder->getFormFactory();
$formConfigBuilder = new FormConfigBuilder('foo', null, $dispatcher);
$formConfigBuilder->setFormFactory($factory);
$formConfigBuilder->setCompound(true);
$formConfigBuilder->setDataMapper($this->createMock(DataMapperInterface::class));
$fooConfig = $formConfigBuilder->getFormConfig();
$form = new Form($fooConfig);
$form->add('save', method_exists(AbstractType::class, 'getBlockPrefix') ? SubmitType::class : 'submit');
$this->serialize($form);
$this->assertTrue(true);
// Exception not thrown
}