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PHP Users::getPosts方法代碼示例

本文整理匯總了PHP中Phosphorum\Models\Users::getPosts方法的典型用法代碼示例。如果您正苦於以下問題:PHP Users::getPosts方法的具體用法?PHP Users::getPosts怎麽用?PHP Users::getPosts使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Phosphorum\Models\Users的用法示例。


在下文中一共展示了Users::getPosts方法的3個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: canHave

 /**
  * Check whether the user can have the badge
  *
  * @param Users $user
  * @return boolean
  */
 public function canHave(Users $user)
 {
     $noBountyCategories = $this->getNoBountyCategories();
     $conditions = 'categories_id NOT IN (' . join(', ', $noBountyCategories) . ') AND accepted_answer = "Y"';
     $posts = $user->getPosts(array($conditions, 'order' => 'created_at DESC'));
     foreach ($posts as $post) {
         $ownReply = $post->countReplies(array("accepted = 'Y' AND users_id = ?0", 'bind' => array($user->id)));
         if ($ownReply) {
             return true;
         }
     }
     return false;
 }
開發者ID:Blkc,項目名稱:forum,代碼行數:19,代碼來源:SelfLearner.php

示例2: canHave

 /**
  * Check whether the user can have the badge
  *
  * @param  Users $user
  * @return boolean
  */
 public function canHave(Users $user)
 {
     $ids = [];
     $noBountyCategories = $this->getNoBountyCategories();
     $conditions = 'categories_id NOT IN (' . join(', ', $noBountyCategories) . ') AND number_views >= 10000';
     $posts = $user->getPosts([$conditions, 'columns' => 'id', 'order' => 'created_at DESC']);
     foreach ($posts as $post) {
         $have = UsersBadges::count(['users_id = ?0 AND badge = ?1 AND type = "P" AND code1 = ?2', 'bind' => [$user->id, $this->getName(), $post->id]]);
         if (!$have) {
             $ids[] = $post->id;
         }
     }
     return $ids;
 }
開發者ID:phalcon,項目名稱:forum,代碼行數:20,代碼來源:FamousQuestion.php

示例3: canHave

 /**
  * Check whether the user can have the badge
  *
  * @param  Users $user
  * @return boolean
  */
 public function canHave(Users $user)
 {
     $ids = array();
     $noBountyCategories = $this->getNoBountyCategories();
     $conditions = 'categories_id NOT IN (' . join(', ', $noBountyCategories) . ') AND
     (IF(votes_up IS NULL, 0, votes_up) - IF(votes_down IS NULL, 0, votes_down)) >= 5';
     $posts = $user->getPosts(array($conditions, 'columns' => 'id', 'order' => 'created_at DESC'));
     foreach ($posts as $post) {
         $have = UsersBadges::count(array('users_id = ?0 AND badge = ?1 AND type = "P" AND code1 = ?2', 'bind' => array($user->id, $this->getName(), $post->id)));
         if (!$have) {
             $ids[] = $post->id;
         }
     }
     return $ids;
 }
開發者ID:kjmtrue,項目名稱:phalcon-tip,代碼行數:21,代碼來源:GoodQuestion.php


注:本文中的Phosphorum\Models\Users::getPosts方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。