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PHP Type::isAbstractType方法代碼示例

本文整理匯總了PHP中GraphQL\Type\Definition\Type::isAbstractType方法的典型用法代碼示例。如果您正苦於以下問題:PHP Type::isAbstractType方法的具體用法?PHP Type::isAbstractType怎麽用?PHP Type::isAbstractType使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在GraphQL\Type\Definition\Type的用法示例。


在下文中一共展示了Type::isAbstractType方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: isTypeSubTypeOf

 /**
  * Provided a type and a super type, return true if the first type is either
  * equal or a subset of the second super type (covariant).
  */
 static function isTypeSubTypeOf(Schema $schema, Type $maybeSubType, Type $superType)
 {
     // Equivalent type is a valid subtype
     if ($maybeSubType === $superType) {
         return true;
     }
     // If superType is non-null, maybeSubType must also be nullable.
     if ($superType instanceof NonNull) {
         if ($maybeSubType instanceof NonNull) {
             return self::isTypeSubTypeOf($schema, $maybeSubType->getWrappedType(), $superType->getWrappedType());
         }
         return false;
     } else {
         if ($maybeSubType instanceof NonNull) {
             // If superType is nullable, maybeSubType may be non-null.
             return self::isTypeSubTypeOf($schema, $maybeSubType->getWrappedType(), $superType);
         }
     }
     // If superType type is a list, maybeSubType type must also be a list.
     if ($superType instanceof ListOfType) {
         if ($maybeSubType instanceof ListOfType) {
             return self::isTypeSubTypeOf($schema, $maybeSubType->getWrappedType(), $superType->getWrappedType());
         }
         return false;
     } else {
         if ($maybeSubType instanceof ListOfType) {
             // If superType is not a list, maybeSubType must also be not a list.
             return false;
         }
     }
     // If superType type is an abstract type, maybeSubType type may be a currently
     // possible object type.
     if (Type::isAbstractType($superType) && $maybeSubType instanceof ObjectType && $schema->isPossibleType($superType, $maybeSubType)) {
         return true;
     }
     // Otherwise, the child type is not a valid subtype of the parent type.
     return false;
 }
開發者ID:aeshion,項目名稱:ZeroPHP,代碼行數:42,代碼來源:TypeInfo.php


注:本文中的GraphQL\Type\Definition\Type::isAbstractType方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。