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PHP ObjectRepository::getPermissionsByRole方法代碼示例

本文整理匯總了PHP中Doctrine\Common\Persistence\ObjectRepository::getPermissionsByRole方法的典型用法代碼示例。如果您正苦於以下問題:PHP ObjectRepository::getPermissionsByRole方法的具體用法?PHP ObjectRepository::getPermissionsByRole怎麽用?PHP ObjectRepository::getPermissionsByRole使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Doctrine\Common\Persistence\ObjectRepository的用法示例。


在下文中一共展示了ObjectRepository::getPermissionsByRole方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: loadUserByUsername

 /**
  * {@inheritdoc}
  */
 public function loadUserByUsername($username)
 {
     $q = $this->userRepository->createQueryBuilder('u')->select('u, r')->leftJoin('u.role', 'r')->where('u.username = :username OR u.email = :username')->setParameter('username', $username)->getQuery();
     $user = $q->getOneOrNullResult();
     if (empty($user)) {
         $message = sprintf('Unable to find an active admin MauticUserBundle:User object identified by "%s".', $username);
         throw new UsernameNotFoundException($message, 0);
     }
     //load permissions
     if ($user->getId()) {
         $permissions = $this->session->get('mautic.user.permissions', false);
         if ($permissions === false) {
             $permissions = $this->permissionRepository->getPermissionsByRole($user->getRole());
             $this->session->set('mautic.user.permissions', $permissions);
         }
         $user->setActivePermissions($permissions);
     }
     return $user;
 }
開發者ID:Jandersolutions,項目名稱:mautic,代碼行數:22,代碼來源:UserProvider.php


注:本文中的Doctrine\Common\Persistence\ObjectRepository::getPermissionsByRole方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。