本文整理匯總了PHP中dektrium\user\models\User::findIdentity方法的典型用法代碼示例。如果您正苦於以下問題：PHP User::findIdentity方法的具體用法？PHP User::findIdentity怎麽用？PHP User::findIdentity使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類dektrium\user\models\User的用法示例。
在下文中一共展示了User::findIdentity方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: behaviors
/**
* @inheritdoc
*/
public function behaviors()
{
return ['access' => ['class' => AccessControl::className(), 'rules' => [['actions' => ['login', 'error'], 'allow' => true, 'roles' => ['?']], ['allow' => true, 'roles' => ['admin']]], 'denyCallback' => function ($rule, $action) {
if (!\Yii::$app->user->isGuest) {
$User = User::findIdentity(Yii::$app->user->getId());
if ($User->getIsAdmin()) {
return $this->redirect(["/user/admin"]);
} else {
Yii::$app->user->logout();
Yii::$app->session->setFlash('type-message', 'text-danger');
Yii::$app->session->setFlash('message', Yii::t('user', 'You don\'t have admin permission'));
}
}
return $this->redirect(["user/login"]);
}], 'verbs' => ['class' => VerbFilter::className(), 'actions' => ['logout' => ['post']]]];
}示例2: testNonExistingUserModel
/**
* @group mandatory
*/
public function testNonExistingUserModel()
{
$identity = User::findIdentity(99999);
$this->assertNull($identity);
}