當前位置: 首頁>>代碼示例>>PHP>>正文


PHP Filesystem::isJunction方法代碼示例

本文整理匯總了PHP中Composer\Util\Filesystem::isJunction方法的典型用法代碼示例。如果您正苦於以下問題:PHP Filesystem::isJunction方法的具體用法?PHP Filesystem::isJunction怎麽用?PHP Filesystem::isJunction使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Composer\Util\Filesystem的用法示例。


在下文中一共展示了Filesystem::isJunction方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: testJunctions

 public function testJunctions()
 {
     @mkdir($this->workingDir . '/real/nesting/testing', 0777, true);
     $fs = new Filesystem();
     // Non-Windows systems do not support this and will return false on all tests, and an exception on creation
     if (!defined('PHP_WINDOWS_VERSION_BUILD')) {
         $this->assertFalse($fs->isJunction($this->workingDir));
         $this->assertFalse($fs->removeJunction($this->workingDir));
         $this->setExpectedException('LogicException', 'not available on non-Windows platform');
     }
     $target = $this->workingDir . '/real/../real/nesting';
     $junction = $this->workingDir . '/junction';
     // Create and detect junction
     $fs->junction($target, $junction);
     $this->assertTrue($fs->isJunction($junction));
     $this->assertFalse($fs->isJunction($target));
     $this->assertTrue($fs->isJunction($target . '/../../junction'));
     $this->assertFalse($fs->isJunction($junction . '/../real'));
     $this->assertTrue($fs->isJunction($junction . '/../junction'));
     // Remove junction
     $this->assertTrue(is_dir($junction));
     $this->assertTrue($fs->removeJunction($junction));
     $this->assertFalse(is_dir($junction));
 }
開發者ID:neon64,項目名稱:composer,代碼行數:24,代碼來源:FilesystemTest.php


注:本文中的Composer\Util\Filesystem::isJunction方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。