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PHP Query::having方法代碼示例

本文整理匯總了PHP中Cake\Database\Query::having方法的典型用法代碼示例。如果您正苦於以下問題:PHP Query::having方法的具體用法?PHP Query::having怎麽用?PHP Query::having使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Cake\Database\Query的用法示例。


在下文中一共展示了Query::having方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: testSelectHaving

 /**
  * Tests that having() behaves pretty much the same as the where() method
  *
  * @return void
  */
 public function testSelectHaving()
 {
     $query = new Query($this->connection);
     $result = $query->select(['total' => 'count(author_id)', 'author_id'])->from('articles')->join(['table' => 'authors', 'alias' => 'a', 'conditions' => 'author_id = a.id'])->group('author_id')->having(['count(author_id) <' => 2], ['count(author_id)' => 'integer'])->execute();
     $expected = [['total' => 1, 'author_id' => 3]];
     $this->assertEquals($expected, $result->fetchAll('assoc'));
     $result = $query->having(['count(author_id)' => 2], ['count(author_id)' => 'integer'], true)->execute();
     $expected = [['total' => 2, 'author_id' => 1]];
     $this->assertEquals($expected, $result->fetchAll('assoc'));
     $result = $query->having(function ($e) {
         return $e->add('count(author_id) = 1 + 1');
     }, [], true)->execute();
     $expected = [['total' => 2, 'author_id' => 1]];
     $this->assertEquals($expected, $result->fetchAll('assoc'));
 }
開發者ID:KarimaLadhani,項目名稱:cakephp,代碼行數:20,代碼來源:QueryTest.php


注:本文中的Cake\Database\Query::having方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。