本文整理匯總了PHP中App\Repositories\UserRepository::getStatut方法的典型用法代碼示例。如果您正苦於以下問題：PHP UserRepository::getStatut方法的具體用法？PHP UserRepository::getStatut怎麽用？PHP UserRepository::getStatut使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類App\Repositories\UserRepository的用法示例。
在下文中一共展示了UserRepository::getStatut方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: indexOrder
/**
* Display a listing of the resource.
*
* @param Illuminate\Http\Request $request
* @return Response
*/
public function indexOrder(Request $request)
{
$statut = $this->user_gestion->getStatut();
$posts = $this->blog_gestion->index(10, $statut == 'admin' ? null : $request->user()->id, $request->input('name'), $request->input('sens'));
$links = str_replace('/?', '?', $posts->render());
return response()->json(['view' => view('back.blog.table', compact('statut', 'posts'))->render(), 'links' => $links]);
}示例2: indexOrder
/**
* Display a listing of the resource.
*
* @param Illuminate\Http\Request $request
* @return Response
*/
public function indexOrder(Request $request)
{
$statut = $this->user_gestion->getStatut();
$posts = $this->blog_gestion->index(10, $statut == 'admin' ? null : $request->user()->id, $request->name, $request->sens);
$links = $posts->appends(['name' => $request->name, 'sens' => $request->sens]);
if ($request->ajax()) {
return response()->json(['view' => view('back.blog.table', compact('statut', 'posts'))->render(), 'links' => $links->setPath('order')->render()]);
}
$links->setPath('')->render();
$order = (object) ['name' => $request->name, 'sens' => 'sort-' . $request->sens];
return view('back.blog.index', compact('posts', 'links', 'order'));
}